Answer:
of cream will remain in the container.
Step-by-step explanation:
Given:
Amount of cream in the container = 
Amount of cream used to make crème brûlée =
We need to find the amount of cream remain in the container.
Solution:
Now we can say that;
the amount of cream remain in the container is equal to Amount of cream in the container minus Amount of cream used to make crème brûlée.
framing in equation form we get;
amount of cream remain in the container = 
Now we will make the denominator common using LCM we get;
amount of cream remain in the container = 
Now denominators are common so we will solve the numerators.
amount of cream remain in the container = 
Hence of cream will remain in the container.
Answer:
1) 48p^2+4p-4
2)40b^2-45b+5
3)3p^2-6p+3
4)3v^2-6v+3
5)40x^2+28x+24
6)3x^2+15x+12
Step-by-step explanation:
Answer:
- A. segment A double prime B double prime = segment AB over 2
Step-by-step explanation:
<u>Triangle ABC with coordinates of:</u>
- A = (-3, 3), B = (1, -3), C = (-3, -3)
<u>Translation (x + 2, y + 0), coordinates will be:</u>
- A' = (-1, 3), B = ( 3, -3), C = (-1, -3)
<u>Dilation by a scale factor of 1/2 from the origin, coordinates will be:</u>
- A'' = (-0.5, 1.5), B'' = (1.5, -1.5), C= (-0.5, -1.5)
<u>Let's find the length of AB and A''B'' using distance formula</u>
- d = √(x2-x1)² + (y2 - y1)²
- AB = √(1-(-3))² + (-3 -3)² = √4²+6² = √16+36 = √52 = 2√13
- A''B'' = √(1.5 - (-0.5)) + (-1.5 - 1.5)² = √2²+3² = √13
<u>We see that </u>
<u>Now the answer options:</u>
A. segment A double prime B double prime = segment AB over 2
B. segment AB = segment A double prime B double prime over 2
- Incorrect. Should be AB = A''B''*2
C. segment AB over segment A double prime B double prime = one half
- Incorrect. Should be AB/A''B'' = 2
D. segment A double prime B double prime over segment AB = 2
- Incorrect. Should be A''B''/AB = 1/2
