Answer:
The terminal point is Q(0,4)
Step-by-step explanation:
We are given the following in the question:
Initial point of vector, P(1,0)
The terminal point Q lies on the y-axis, thus Q have coordinates of the form:
The magnitude of the vector is 
Magnitude is given by:
But since the terminal point is above the initial point, thus,
Thus, the terminal point is Q(0,4)
I can only assume that you meant, "Solve for x:"
Apply the exponent 3/2 to both sides of this equation. The result will be
3/2
343 = x/6.
Multiplying both sides by 6 isolates x:
3/2
6*343 = x Since 7^3 = 343, the expression for x
can be rewritten as
3/2
6*(7^3) = x which can be further simplified, as follows:
x = 6^(3/2)*7^(9/2), or:
x = 6^(3/2)*7^(8/2)*√7, or
x = 6^(3/2)*7^4*√7
Answer:
$14.98
Step-by-step explanation:
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