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Molodets [167]
3 years ago
14

In 1997, the American Diabetes Association (ADA) and the federal government lowered the standard for diagnosing diabetes from a

fasting blood glucose level of 140 mg/dL to 126 mg/dL.7. What is the proportion of people who are considered have diabetes and they were not considered have diabetes before 1997
Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

Answer:

10 percent

Step-by-step explanation:

- Before 1997, people with a minimum FBGL of 140mg/dl were diagnosed as diabetic

- After 1997, people with a minimum FBGL of 126mg/dl were diagnosed as diabetic

- What is the proportion of people who were not considered diabetic before 1997 but are now considered diabetic (after 1997)?

140 - 126 = 14

In percentage, this proportion is = 14/140 × 100

= 10%

Hence, 10% of the people who were not considered diabetic before 1997 are now or will now be considered diabetic.

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Ahat [919]

Answer:

D. f(x) = 2\cdot x^{2}-4\cdot x -16

Step-by-step explanation:

Any parabola is modelled by a second-order polynomial, whose standard form is:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

a, b, c - Coefficients, dimensionless.

In addition, a system of three linear equations is constructed by using all known inputs:

(-2, 0)

4\cdot a -2\cdot b + c = 0 (Eq. 1)

(4, 0)

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c = -16 (Eq. 3)

Then,

4\cdot a - 2\cdot b = 16 (Eq. 4)

16\cdot a + 4\cdot b = 16 (Eq. 5)

(Eq. 3 in Eqs. 1 - 2)

a - 0.5\cdot b = 4 By Eq. 4 (Eq. 4b)

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64 + 12\cdot b = 16

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The remaining coeffcient is:

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a = 4 + 0.5\cdot (-4)

a = 2

The function that represents a parabola with zeroes at x = -2 and x = 4 and y-intercept (0,16) is f(x) = 2\cdot x^{2}-4\cdot x -16. Thus, the right answer is D.

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Step-by-step explanation:

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Part A:

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