Answer:
θ = 5π/6 rad and 11π/6 rad
Step-by-step explanation:
Given the expression cotθ+√3=0
Subtract √3 from both sides
cotθ+√3-√3=0-√3
cotθ = -√3
Since cotθ = 1/tanθ
1/tanθ = -√3
Reciprocate both sides:
tanθ = -1/√3
θ = tan^-1(-1/√3)
θ = -30°
Since the angle is negative, and tanθ is negative in the second and fourth quadrant.
In the second quadrant;
θ = 180-30
θ = 150°
Since 180° = πrad
150° = 150π/180
150° = 5π/6 rad
In the fourth quadrant;
θ = 360-30
θ = 330°
Since 180° = πrad
330° = 330π/180
330° = 11π/6 rad
Hence the solutions are 5π/6 rad and 11π/6 rad.
Given the position function <em>s(t)</em>, you can get the acceleration function by differentiating <em>s</em> twice:
velocity = <em>s'(t)</em> = -5 sin(<em>t </em>) + 3 cos(3<em>t</em> )
acceleration = <em>s''(t)</em> = -5 cos(<em>t</em> ) - 9 sin(3<em>t</em> )
Then when <em>t</em> = <em>π</em>, the particle's acceleration is
<em>s''(π)</em> = -5 cos(<em>π</em>) - 9 sin(3<em>π</em>)
… = -5 • (-1) - 9 • 0 = 5
Answer:
144 and 18
Step-by-step explanation:
18 ×24=432÷3=144
Answer:
The new point is at (5, -5)
Step-by-step explanation:
When a point is being translated down, they are being subtracted on the y-value. So all you have to do is subtract 9 from 4 and we end up with -5, our new y-value.
(5, -5)
Answer:
n = 6.39
Explanation:
2.3 + 4.09 = n
6.39 = n
Swap the sides of the equation
n = 6.39
