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Pavlova-9 [17]
3 years ago
9

A man pushes a lawn mower on a level lawn with a force of 250N. If 40% of this force is directed downward, how much work is done

in joules by the man in pushing the mower 6.2 m?
Physics
1 answer:
Dvinal [7]3 years ago
4 0
When considering work, we always take the force directed along the axis of motion (in this case, the horizontal axis). If 40% of the force is directed downward, then 60% of the force is being directed horizontally, so the horizontal force is 250*0.6 = 150N. Work = Force * distance = 150N * 6.2m = 930J
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A stone with a weight of 5.29 N is launched vertically from ground level with an initial speed of 26.0 m/s, and the air drag on
makkiz [27]

Answer:

a) 19.4 m/s

b) 19 m/s

Explanation:

a) In the given question,

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the potential energy at the final point = Uf = mgh

the kinetic energy at the initial point = Ki = 1/2 mv₀².

the kinetic energy at the final point = Kf = 0

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Now, using the law of conservation of energy

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1/2 mv₀² + 0 = 0 + mgh + fh

1/2 mv₀² = mgh + fh

h = v₀²/ 2g (1 +f/w)

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= 0.54 kg

h = 20 ²/ (2 x9.80) x (1 0.265/5.29)

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6 0
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Answer:

true

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Aloiza [94]

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