Which values are solutions to the inequality –3x – 4 < 2? Check all of the boxes that apply. -4 -2 0 3

Mathematics

2 answers:

Blizzard [7]2 years ago

8 0

Answer:

0 and 3

Step-by-step explanation:

We are given that an inequality

$-3x-4< 2$

Adding 4 on both sides of inequality

$-3x-4+4$

$-3x< 6$

Divide by 3 on both sides of inequality

$-x$

$x > -2$

$x\in(-\infty,-2)$

The solutions of given inequality are 0 and 3.

Answer:0 and 3

Aleonysh [2.5K]2 years ago

6 0

Zero and three...........

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77julia77 [94]

I am sorry, I would love to help but I am not sure. Good luck anyways. :(

7 0

3 years ago

I really need help if anyone can help that would be great

Oliga [24]

Factor the denominator:

(3x-1)(x+2)

every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.

since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.

the answer here is C.

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3 years ago

PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4

Goshia [24]

Answer:

$\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

Step-by-step explanation:

$y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\$

$\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$