According to the rule of angles and parallel lines, we can say that ∠NKM and ∠KML are equal because they are alternate angles. Since MP is a bisector, ∠KMP = ∠LMP = 1/2∠NKM = 29°. We know that ∠MKL = 90°-∠NKM = 32°. According to the sum of all angles of the triangle, ∠KPM = 180-(32+29) = 119°.
The answer is 242 cm squared.
6(y+z)
--------
yz
I believe this is the answer you are looking for
Answer:
Step-by-step explanation:
The answer to this problem is C
Answer: Choice A) 66 degrees
========================================================
Minor arc AB (marked in red in the attached diagram) is 45 degrees
Minor arc BE (marked in blue in the same diagram) is 87 degrees
Add the two arcs: 45+87 = 132
Then cut this value in half to get the inscribed angle ADE
132/2 = 66
We cut it in half due to the inscribed angle theorem
Notice how angle ADE cuts off arc ABE (which is composed of minor arc AB and and minor arc BE)
