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marishachu [46]
4 years ago
6

Need help asap!!! plzz

Mathematics
1 answer:
MA_775_DIABLO [31]4 years ago
8 0

B is the correct answer

:)

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What is the correct words for the number 0.9.​
Usimov [2.4K]

Answer:

\Huge\sf{Answer}

Zero point nine = 0.9

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3 years ago
Can somebody help me with my math? <br> Answer ASAP cause nobody will
marta [7]

Answer:

WHAT'S THE MATH PROBLEM?

Step-by-step explanation:

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3 years ago
What times what equals -4.75 but added together equals -9
ladessa [460]
-9.5 and 0.5
There isnt really a method of finding this, trial and error
5 0
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You are part of a construction company that is supposed to build houses. An architect has left plans to build houses on each isl
Marrrta [24]

Answer:

<h2>Island A, B and C has 10, 5 and 7 houses respectively.</h2>

Step-by-step explanation:

Let, the three islands A, B and C has a, b and c houses respectively.

According to the question, a + b = 15; a + c = 17; b + c = 12; a + b + c = 22.

Adding [ a + b = 15; a + c = 17]-these two, we get, a + (a + b + c) = 15 + 17 = 32\\a + 22 = 32\\a = 10.

Now, a + b = 15\\10 + b = 15\\b = 5.

a + c = 17\\10 + c = 17\\c = 7.

7 0
4 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
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