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3 years ago

For a given rectangle the length equal 3x + 2 and the width equal 5 what is the area of the rectangle

Mathematics

2 answers:

MrMuchimi3 years ago

7 0

Answer:

15x+10 units ^2

Step-by-step explanation:

The area of a rectangle can be found using:

A = l * w

The length of the rectangle is 3x+2 and the width is 5.

l=3x+2

w=5

Substitute these values into the formula.

A= 3x+2 *5

This can be rewritten as: (Commutative property of Multiplication)

A= 5* 3x+2

A= 5(3x+2)

Distribute the 5. Multiply each term inside the parentheses by the number outside the parentheses.

A= (5*3x) + (5*2)

A= 15x +10

A= 15x+10 units^2

The area of the rectangle is 15x+10 square units.

Anvisha [2.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

To find the area of a rectangle, recall the formula is A = l × w. Therefore:

A = (3x + 2) (5)

Distribute the '5':

A = 15x + 10

Therefore, the area of the rectangle of <u>15x + 10.</u>

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Answer:

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4. g = -2

6. t = 21

8. n = 4

10. y = -1

Step-by-step explanation:

2. 63 = -3(1 - 2n)

Dividing both the side by negative 3 we get

$-21=1-2n\\2n=1+21\\2n=22\\n=\frac{22}{2} \\\therefore n=11$

4. -g + 2(3 + g) = -4(g + 1)

First we will open the bracket by distributive property A( B +C) = AB + AC

$-g+2\times 3 + 2\times g = -4\times g + -4\times 1\\-g+6+ 2g=-4g-4\\\textrm{we will take all the g term the left side and the constant to the right side}\\4g-g+2g=-6-4\\5g=-10\\g=\frac{-10}{5}\\\therefore g=-2$

6.-3(t +5 ) + (4t + 2) = 8

Using distributive property A( B +C) = AB + AC we get

$-3\times t + -3\times 5 + 4t + 2=8\\-3t-15+ 4t + 2=8\\t=8+15-2\\t=21\\\therefore t=21\\$

8. -8 - n = -3(2n -4)

Using distributive property A( B +C) = AB + AC we get

$-8 - n = -3\times 2n - -3\times4\\-8-n=-6n+12\\\textrm{all the n terms to the left inside and the constant of the right-hand side}\\6n-n=8+12\\5n=20\\n=\frac{20}{5}\\ \therefore n= 4$

10. -4( 2 - y) + 3y = 3(y - 4)

Using distributive property A( B +C) = AB + AC we get

$-4\times 2 --4\times y + 3y = 3\times y -3\times 4\\-8+4y+3y =3y-12\\\textrm{all the y terms to the left side and the constant to the right side}\\4y+3y-3y=-12+8\\4y=-4\\y=\frac{-4}{4}\\ \therefore y=-1$

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