At a fair, each person can spin two wheels of chance. The fist wheel has numbers 1,2, and 3. The second wheel has the letters A

Question

3 years ago

7

At a fair, each person can spin two wheels of chance. The fist wheel has numbers 1,2, and 3. The second wheel has the letters A

and B. (A) list all the possible outcomes of the computed event. (B) if you spin both wheels, what is the probability that you get either a 1 or an A? Explain.

Mathematics

2 answers:

AlexFokin [52] · Answer 1 · 2022-05-29T23:19:49+03:00

AlexFokin [52]3 years ago

7 0

The answer to Part (B) is 4/6

nydimaria [60] · Answer 2 · 2022-05-30T00:34:55+03:00

(a) There are 3 numbers on the fist well and 2 letters on the second, so number of possible outcomes = 3*2 = 6 possible outcomes

The possible outcomes are 1A, 2A, 3A, 1B, 2B, 3B

So in total there are 6 possible outcomes as shown above if a person can spin the two wheels

(b) From possible outcomes A or 1 can appear four times namely: 1A,2A,3A and 1B

So probability is number of successes/ total number = 4/6