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3 years ago

15 = -3(2c + d) (Solve for c)

Mathematics

1 answer:

Paha777 [63]3 years ago

7 0

Answer:

(15+3d)/6 = c

2 1/2 + 1/2d = c (more simplified)

Step-by-step explanation:

15 = -3(2c +d)

15 = -6c -3d

+3d +3d

15 +3d = -6c

/-6 /-6

(15+3d)/6 = c

2 1/2 + 1/2d = c

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The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?

adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)$

$\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}$

$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$

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2 years ago

Rewrite the parametric equations by eliminating the parameter. Select ONE.

Vinil7 [7]

Answer:

$Y=(X-7)/2$

Step-by-step explanation:

we have

$X=2t+3$ -----> equation A

$Y=t-2$ -----> $t=Y+2$ -----> equation B

Substitute equation B in equation A

$X=2(Y+2)+3$

$X=2Y+4+3$

$X=2Y+7$

solve for Y

$2Y=X-7$

$Y=(X-7)/2$

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2 years ago

What is (5x-2)(4x^2 -3x-2)

Ronch [10]

Answer: 20x^3 - 23x^2 - 4x + 4

Explanation:

Use distributive property:

(5x-2)(4x^2 - 3x-2)
= 20x^3 - 15x^2 - 10x - 8x^2 + 6x + 4
= 20x^3 - 23x^2 - 4x + 4

8 0

2 years ago

Read 2 more answers

Determine if Ginny factored correctly. If not, explain where she made an error. Ginny made a mistake in step 1 when she identifi

il63 [147K]

Quadratic equations are second-order equations. Ginney made a mistake when she identified b = 31. It should be b = –31.

<h3>What is a Quadratic Equation?</h3>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

In order to find the mistake that Ginny made, we will first find the factors ourselves, therefore, we will factorize the trinomial,

$6x^2 - 31x -30 = 0$

As we can see that the value of constants are,

a = 6

b = -31

c = 30

$6x^2 - 31x -30 = 0\\\\6x^2 - 36x+5x -30 = 0\\\\6x(x-6)+5(x-6)=0\\\\(6x+5)(x-6)=0$

Therefore, the factors of the trinomial $6x^2 - 31x -30 = 0$ are (6x+5) and (x-6).

If we compare our process with Ginny's process, we will find that she has taken the value of the constant b as 31 which is wrong.

Hence, Ginney made a mistake when she identified b = 31. It should be b = –31.

Learn more about Quadratic Equation:

brainly.com/question/17177510

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2 years ago

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If the weight (in grams) of cereal in a box of Lucky Charms is N(489,6), what is the probability that the box will contain less

Wittaler [7]

Answer:

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

N(489,6)

This means that $\mu = 489, \sigma = 6$

What is the probability that the box will contain less than the advertised weight of 466 g?

This is the p-value of Z when X = 466. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{466 - 489}{6}$

$Z = -3.83$

$Z = -3.83$ has a p-value of 0.000064

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

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2 years ago

15 = -3(2c + d) (Solve for c)​

15 = -3(2c + d) (Solve for c)