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avanturin [10]
3 years ago
13

A=V1-V0/t solve for V1

Mathematics
2 answers:
enyata [817]3 years ago
8 0
For this case we have the following equation:
 A =  \frac{v1-v0}{t}
 From here, we must clear the value of v1.
 For this, we follow the following steps:
 1) Pass variable t to multiply:
 A*t  = v1 - v0
 2) Add v0 on both sides of the equation:
 A*t+v0=v1-v0+v0
 3) Rewrite the expression:
 A*t+v0=v1
 Answer:
 
The resolved expression for v1 is:
 
v1 = A*t+v0
MA_775_DIABLO [31]3 years ago
6 0
 A = V1 - V0/t.....multiply both sides by t
At = V1 - V0....add V0 to both sides
At + V0 = V1
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The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

                 Given diagram is combination of Rectangle and Semi circle.

Step:1

         Res the attachment,

                      Area of given diagram = Area of A + Area of B..............(1)

Step:2

         For A,

         The A section in the given diagram is semi circle,

                     Diameter of semi circle = Total distance - ( 2+3)

                                          ( ∵ 2, 3 are top distance in the given diagram)

                                                             = 10 - 5

                                        Diameter, d = 5 cm

                                             Radius, r = \frac{d}{2}

                                                          r = \frac{5}{2}

                                                         r = 2.5 cm

                                          Area, A_{A}  = \frac {\pi r^{2} }{2}........................(2)

                                                    A_{A}  = \frac {\pi (2.5)^{2} }{2}  

                                                           = \frac {\pi ( 6.25) }{2}

                                                           = \frac{19.63}{2}

                                                     A_{A} = 9.8174 cm^{2}

Step:3

               For B,

               Area of rectangle is,

                                                      A_{B} =lb.....................(3)

              Where, l - Length = 10 cm

                          b - Width = 2 cm

              Equation (3) become,

                                                            = (10)(2)

                                                            = 20

                                    Area of B, A_{B} = 20 cm^{2}

Step:4

               From the equation (1),

                               Area of given diagram = 20+ 9.81747

                                                            Area = 29.817 square centimeters

Result:

            The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

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