Answer:
Volume of the cone = 130.83 cubic units
Step-by-step explanation:
The question us incomplete without the diagram of the cone and it's dimensions as this would enable us get the exact answer.
Find attached the diagram used in solving the solution.
Volume of cone = ⅓ πr²h
Radius = r = 5 unit
Height = h = 5 unit
π = 3.14
By inserting the values of each variables, we have:
Volume of cone = ⅓ × 3.14× (5)² × 5
= ⅓ × 3.14× 25×5 = ⅓ × 3.14×125
Volume of cone = (392.5)/3
Volume of cone = 130.8333
Volume of cone = 130.83 cubic units (to the nearest hundredth)
Volume of cone = 130.83 unit³
The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4
At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5
-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5
This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!
I'm thinking you would have to add the probabilities that you choose a boy with you choose someone in the science club minus a boy in the science club. You can't count these people twice.
I'm getting 59%
(11+10-2)/32
Answer:
m∠R = 123°
m∠S = 91°
Step-by-step explanation:
The measure of an inscribed angle is 1/2 the measure of the intercepted arc
m of arc QRS = 2 m∠P = 2(57) = 114
Now m of arc SPQ = 360 - 114 = 246
So, m∠R = 1/2(246) = 123
m of arc RSP = 2 m∠Q = 2(89) = 178
m of arc PQR = 360 - 178 = 182
m∠S = 1/2(182) = 91
Answer:
part A :BODMAS ( Bracket of Division Multiplication Addition Subtraction )
part b; Bracket (2+3.2) = - 2- 3.2
= 16- 2-3.2 +30-5
ADDITION:-3.2+30 = - 33.2
16-2(-33.2)30-5
14-33.2 +30-5
14-33.2 +25
-19.2+25
-44.2
Step-by-step explanation:
THE FOLLOWING EQUATION CAN ONLY BE SOLVED USING BODMAS
