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3 years ago

Which solution will form a precipitate when mixed with a solution of aqueous Na2CO3?

Chemistry

2 answers:

Harlamova29_29 [7]3 years ago

8 0

Answer:

When mixed with a solution of aqueous sodium carbonate, a solution containing copper (II) ions will form a precipitate.

Explanation:

A precipitation reaction is a reaction in which one of the products is insoluble in the solvent of the reaction (this is usually water).

These reactions are one of the types of double-displacement reactions in which the cations and anions of the reactants are inter-changed.

When mixed with a solution of aqueous sodium carbonate, a solution containing copper (II) ions will form a precipitate which is insoluble in water.

The copper (II) ions will form together with the carbonate, a precipitate. Which will be insoluble. An example is CuSO4.

Na2CO3 + CuSO4 → 2Na+ + CO32- + Cu+ + SO42- →2Na+ + SO42- + CUCO3

Musya8 [376]3 years ago

8 0

Answer:

Cu²+ ions

Explanation:

A solution of copper(ii) ions will form a precipitate with Na2CO3 due to CuCO3 is insoluble.

Equation of reaction.

CuCl₂ +Na₂CO₃ → CuCO₃ + 2NaCl

CuCO₃ is insoluble and quickly forms a precipitate.

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Problem page in each of the molecules drawn below one chemical bond is colored red. decide whether this bond is likely to be pol

Slav-nsk [51]

The question is incomplete, here is the complete question:

Problem page in each of the molecules drawn below one chemical bond is colored red. Decide whether this bond is likely to be polar or not. if the bond is likely to be polar, write down the chemical symbol for the atom which will have more negative charge.

The image is attached below.

Answer:

For carbon dioxide molecule: The bond is considered as polar and the elecvtronegative atom is oxygen.

For water molecule: The bond is considered as polar and the elecvtronegative atom is oxygen.

Explanation:

There are two types of covalent bonds:

Polar covalent bond: This bond is formed when difference in electronegativity between the atoms is present. When atoms of different elements combine, it results in the formation of polar covalent bond. For Example: $CO_2,NO_2$ etc..
Non-polar covalent bond: This bond is formed when there is no difference in electronegativity between the atoms. When atoms of the same element combine, it results in the formation of non-polar covalent bond. For Example: $N_2,O_2$ etc..

In carbon dioxide molecule:

The given bond is present between C and O atom.

Electronegativity value of C = 2.5

Electronegativity value of O = 3.5

Electronegativity difference = (3.5 - 2.5) = 1

As, electronegativity difference is present. So, the bond is considered as polar and the elecvtronegative atom is oxygen.

In water molecule:

The given bond is present between H and O atom.

Electronegativity value of H = 2.1

Electronegativity value of O = 3.5

Electronegativity difference = (3.5 - 2.1) = 1.4

As, electronegativity difference is present. So, the bond is considered as polar and the elecvtronegative atom is oxygen.

8 0

4 years ago

Which of the following best explains why a structural formula of a chemical compound is more useful than a molecular formula?

Ganezh [65]

Answer: the correct answer is (A).

Explanation:

Structural formula not only tells us about the number and types of atoms in a molecule but also tells us about the bonded positions of all the atoms in a molecule of that particular compound.

Molecular structure only tells us about the numbers of atoms and types of atoms present in a molecule of that particular compound.

For example: Molecular formula of propanone and propanal are same that is $C_3H_6O$ but structural formula is different that $CH_3COCH_3$ for propane and $CH_3CH_2CHO$ for propanal. Here structural formula is showing that how the atoms in propanone and propanal are bonded together.

Hence, the correct answer is option (A).

5 0

3 years ago

Read 2 more answers

Does wind speed affect evaporation? How?

garik1379 [7]

Answer:

Wind moving over a water or land surface can also carry away water vapor, essentially drying the air, which leads to increased evaporation rates.

3 0

3 years ago

Read 2 more answers

You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,

telo118 [61]

Answer:

$\frac{[F^{-}]}{[HF]}$ is larger

Explanation:

$pK_{a}=-logK_{a}$ , where $K_{a}$ is the acid dissociation constant.

For a monoprotic acid e.g. HA, $K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}$ and $\frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}$

So, clearly, higher the $K_{a}$ value , lower will the the $pK_{a}$

In this mixture, at equilibrium, $[H^{+}]$ will be constant.

$K_{a}$ of HF is grater than $K_{a}$ of HCN

Hence, $(\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})$

So, $\frac{[F^{-}]}{[HF]}$ is larger

8 0

4 years ago

A. Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculat

liraira [26]

Answer:

A)Mass of gallium plated out is 0.3440 grams

B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

Explanation:

To calculate the total charge, we use the equation:

$C=I\times t$

where,

C = Charge

I = Current in time t (seconds)

To calculate the moles of electrons, we use the equation:

$\text{Moles of electrons}=\frac{C}{F}$

where,

F = Faraday's constant = 96500

A) The equation for the deposition of Ga(s) from Ga(III) solution follows:

$Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)$

I = 0.790 A, t = 30.0 min = 1800 seconds

$C=I\times t$

$C=0.790 A\times 1800 s=1422 C$

Moles of electron transferred:

$=\frac{1422 C}{96500 F}=0.01474 mol$

Now, to calculate the moles of gallium, we use the equation:

$\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}$

n = number of electrons transferred = 3

$\text{Moles of Gallium}=\frac{0.01474 mol}{3}=0.004913 mol$

Mass of 0.004913 moles of gallium = 0.004913 mol × 70 g/mol=0.3440 g

B) The equation for the deposition of Sn(s) from Sn(II) solution follows:

$Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$

Moles of tin = $\frac{8.70 g}{119 g/mol}=0.07311 mol$

n = number of electrons transferred = 2

$\text{Moles of tin}=\frac{\text{Moles of electrons}}{n}$

Moles of electron = $n\times \text{Moles of tin}$

$=2\times 0.07311 mol=0.14622 mol$

Charge transferred during time t :

$\text{Moles of electrons}=\frac{C}{F}$

$C=96500 F\times 0.14622 mol=14,110.23 C$

Current applied for t time = I = 5.79 A

$t=\frac{C}{I}=\frac{14,110.23 C}{5.79 A}=2,437 s=0.67 hrs$

For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

5 0

4 years ago