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PilotLPTM [1.2K]
3 years ago
15

Why metals are good conductors

Chemistry
2 answers:
marysya [2.9K]3 years ago
8 0
Metals allow electric charge to move freely through them. Metals have a sea of delocalized electrons that are able to move freely throughout the metal structure.

Please make brainliest answer I need one more <3
stepan [7]3 years ago
7 0

Answer is: because of delocalized electrons in metallic bond.

Substances with metallic bond conduct an electric current in liquid and solid state, because they have mobile electrons.

Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.

1. Metallic bond is a type of chemical bond.  

2. Metallic bond is formed between electrons and positively charged metal ions.  

3. Metallic radius is defined as one-half of the distance between the two adjacent metal ions.  

4. Metallic bond increace electrical and thermal conductivity.  

5. Metals conduct heat, because when free moving electrons gain energy (heat) they vibrate more quickly and can move around.

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In a galvanic cell, electrons are transferred from one half cell to the other as the redox reaction progresses. what happens in
Sidana [21]

The half cell in which the electrode gains electrons is where reduction occurs, and the half cell in which the electrode loses electrons is where oxidation occurs.

<h3><u>What is a Galvanic cell ?</u></h3>

Voltaic or galvanic cells are electrochemical devices that use spontaneous oxidation-reduction events to generate electricity. In order to balance the overall equation and highlight the actual chemical changes, it is frequently advantageous to divide the oxidation-reduction reactions into half-reactions while constructing the equations.

Two half-cells make up most electrochemical cells. The half-cells allow electricity to pass via an external wire by separating the oxidation half-reaction from the reduction half-reaction.

<h3><u>Oxidation:</u></h3>

The anode is located in one half-cell, which is often shown on the left side of a figure. On the anode, oxidation takes place. In the opposite half-cell, the anode and cathode are linked.

<h3><u>Reduction:</u></h3>

The second half-cell, cathode, which is frequently displayed on a figure's right side. The cathode is where reduction happens. The circuit is completed and current can flow by adding a salt bridge.

To know more about processes in Galvanic cell, refer to:

brainly.com/question/13031093

#SPJ4

7 0
1 year ago
Question 6 of 10
Levart [38]

Answer:

C. Solids made of molecules

3 0
3 years ago
Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o
sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4}  } = 0.0106 M

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%

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how much hydrogen gas is necessary to exert a pressure of 1.4 ATM at 430k if occupying a volume of 15.1 l
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Answer:

5

Explanation:

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Explanation:

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