Answer:
It is not a subspace.
Step-by-step explanation:
So, the polynomial degree of at most 3 is given below as;
V = { p (z) = b0 + b1z + b2z^ + ... + bnz^n. |n is less than or equal to 3 and b0, b1, b2,... are integers.
To determine whether a subset is a subspace of Pn, we have to check for the properties below;
(1). Zero vector property : that is, when polynomial, p(z) = 0 and 0 is an integer.
(2). Addition property= here, we have; p(z) + h(z) = (b0 + b1z + b2z^2 +....+ bnz^n) + ( c0 + c1z + c^2z^2 +... + cnz^n). That is the sum of integers.
(3). Scaler multiplication property: the coefficient here may not be real numbers therefore, the condition is not followed here.
Therefore, it is not a subspace of Pn.
ANSWER: 40
EXPLANATION:
1) 40.73 to 1 significant figure = 40.
2) 1.06 to 1 significant figure = 1.
3) Therefore, we just multiply 40 by 1, which equals 40.
FURTHER EXPLANATION (IF NEEDED):
With significant figures, whole numbers such as 10, 20, 50 etc. have 1 significant figure. This is because the 0 does not count as a significant figure.
With decimals, all numbers after the decimal point are also included as significant figures (even 0). E.g. 40.73 has 4 significant figures and 1.06 has 3 significant figures.
EXAMPLES (IF NEEDED):
Rounding to 2 significant figures:
Rounding to 3 significant figures:
- 40.73 = 40.7
- 1.06 = 1.06 (because it's already in 3 significant figures)
Rounding to 4 significant figures:
- 40.73 = 40.73 (already in 4 significant figures)
- 1.06 = 1.060 (0 is counted as a significant figure if there is a decimal or another number comes after that 0)
E.g. 1006 has 4 sig figs, while 1060 would have 3 sig figs because the last 0 is not counted as a significant figure. 10.60 would have 4 sig figs because of the decimal.
the answer is 2. because you need to subtract the fractions once you do that you’ll get -2 • (-1) then multiple you’ll have 2 .
Answer:
6.5
Step-by-step explanation:
3X5=15
97.5/ 15 = 6.5
