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Vladimir [108]
3 years ago
12

What is the area of the shape?​

Mathematics
2 answers:
Dominik [7]3 years ago
8 0

Answer:

20 is the answer :))))

20

coldgirl [10]3 years ago
7 0
The answer is 20!!!!
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4x -5 = 2(2x +1)<br> I need help
Nostrana [21]

Answer:

No Solution

Step-by-step explanation:

4x-5=2\left(2x+1\right)

Expand:

4x-5=2* \:2x+2* \:1

4x-5=4x+2

Add 5 to both sides:

4x-5+5=4x+2+5

4x=4x+7

Subtract 4x from both sides:

4x-4x=4x+7-4x

0=7

No solution as this is false.

4 0
3 years ago
Read 2 more answers
What properties can be used to solve 7y-15=-29. Identity property of multiplication,addition property of equality ,distributive
Sveta_85 [38]

Answer:

Addition Property of Equality.

Inverse property of multiplication.

Step-by-step explanation:

Given the equation:

7y-15=-29

First of all, let us use Addition Property of Equality.

According to the property, if we add a number on both sides of an equality, there is no change in the equality.

In other words, the equality will be same if we add the same number on Left Hand Side and Right Hand Side of the equality.

First of all, let us add 15 on both sides of the equality:

7y-15+15=-29+15\\\Rightarrow 7y=-14

Now, let us Inverse property of multiplication.

i.e. Multiplication of a number with its inverse is equal to 1.

a\times \frac{1}{a} = 1

So, let us multiply the given equation with \frac{1}7

7y \times \dfrac{1}{7}=-14 \times \dfrac{1}{7}\\\Rightarrow 1y =-2\\\Rightarrow y=-2

The properties used are:

Addition Property of Equality.

Inverse property of multiplication.

7 0
3 years ago
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
3 years ago
Help Find AB please explain
agasfer [191]

Answer:

AB=2\sqrt{29}

Step-by-step explanation:

Hope it helps you in your learning process.

7 0
3 years ago
Solve please help<br> What's the answer
Nady [450]
Answer is 4 I think so yeah
4 0
3 years ago
Read 2 more answers
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