All categories

3 years ago

How many kilometers are in 31,800,000 centimeters?

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

3 0

There are 318 kilometers in 318000000 centimeters.

You might be interested in

Seth is trying to find the unit price for a package of blank compact discs on sale at 10 for $5.49. Find his mistake and correct

uysha [10]

If you do not mind me asking, what did Seth write? Us helpers cannot answer it if we do not have the full question. I apologize if this seems rude.

6 0

3 years ago

Read 2 more answers

4x + y = 10 7x + 2y = 17

Nezavi [6.7K]

Answer:

x = 3, y = - 2

Step-by-step explanation:

By substitution method,

4x + y = 10 -------> equation 1.

7x + 2y = 17 -------> equation 2.

From equation 1,

y = 10 - 4x ------> equation 3.

Substitute equation 3 in 2,

7x + 2 ( 10 - 4x ) = 17

7x + 20 - 8x = 17

7x - 8x = 17 - 20

- x = - 3

x = 3

Substitute x = 3 in equation 1,

4 ( 3 ) + y = 10

12 + y = 10

y = 10 - 12

y = - 2

Hence,

x = 3

y = - 2

6 0

2 years ago

Read 2 more answers

What is the value of y in the equation 5x+2y=20 when x=0.3

MakcuM [25]

5 multiplied by .3 is 1.5
1.5 + 18.5 = 20.
y = 9.25

3 0

3 years ago

The three inside angles (A,B and C) of a right-angled triangle are in the ratio 7:18:11. Th smallest angle is 35. Work out angle

lions [1.4K]

Answer:

<A = 35degrees

<B =90degrees

<C = 55degrees

Step-by-step explanation:

Given the ratios of a triangle as 7:18:11

Total ratio = 7+18+11

Total ratio = 36

Since the smallest angle is 35degrees, hence <A = 35degrees

Get angle B;

<B = 18/36 * 180 (sum of angle in a triangle is 180degrees)

<B = 1/2 * 180

<B = 90degrees

Get angle C;

<C = 11/36 * 180

<C = 11 * 5

<C = 55degrees

Hence the value of A, B and C are 35, 90 and 55 degrees repectively

3 0

3 years ago

Traveling math word problem - thank you! :)

Anni [7]

We are given:

car and train leave at the same time

average velocity of car = 50 miles/hour

average velocity of train = 70 miles/hour

train arrives 2 hours early

Assuming variables and making equations!

let the time taken by the train = t hours

since the car arrived late, it took more time as compared to the train

time taken by the car = t + 2 hours

since the distance from Pasadena to Sacramento doesn't change, both the vehicles covered the same distance, d

Distance travelled by the car:

d = 50 $\frac{miles}{hour}$ * (t+2) hours [distance = velocity * time]

d = 50(t+2) miles

rewriting in terms of t

$t = \frac{d-100}{50}$

Distance travelled by the train:

d = 70 $\frac{miles}{hour}$ * t hours

d = 70t miles

rewriting in terms of t

$t = \frac{d}{70}$

now we have two expressions for t, both of which are equal because t is just the time taken by the train

Finding the distance:

$t = \frac{d-100}{50}$

$t = \frac{d}{70}$

because t is the same:

$\frac{d-100}{50} = \frac{d}{70}$

$\frac{d-100}{5} = \frac{d}{7}$

7(d - 100) = 5(d)

7d - 700 = 5d

(7d - 5d) - 700 = 0 [subtracting 5d from both sides]

2d = 700 [adding 700 on both sides]

d = 350 miles [dividing both sides by 2]

The distance between Pasadena and Sacramento is 350 miles!

7 0

2 years ago