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ArbitrLikvidat [17]
3 years ago
12

How many kilometers are in 31,800,000 centimeters?

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0
There are 318 kilometers in 318000000 centimeters. <span />
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Help on #51 please !!
Aleks04 [339]

Answer:

53. ±6

51. 2

Step-by-step explanation:

According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], in this case, evaluate everything in grouping symbols first, then evaluate the exponents to avoid confusion:

\sqrt{(32 + {2}^{3} - 4)} = \sqrt{32 + 8 - 4} = \sqrt{36} = ±6 \\  \\ (17 - 11 + {4}^{2}) \div 11 = (17 - 11 + 16) \div 11 = \\  \\ 22 \div 11 = 2

I am joyous to assist you anytime.

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4 years ago
The ____ consists of all the ordered pairs that satisfy all the inequalities in the system
Ostrovityanka [42]
Solution of a set of linear inequalities consists all the ordered pair that satisfy all the linear inequalities in the system.
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3 years ago
At a coffee shop, the first 100 customers'<br> orders were as follows.
iris [78.8K]

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3 years ago
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Integers that are not whole numbers are
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3 years ago
If y=(x^2-4)^5(3x+4)^4
alexira [117]

Answer:

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

Step-by-step explanation:

y=(x^2-4)^5(3x+4)^4

y'=[\frac{d}{dx}(x^2-4)^5](3x+4)^4+(x^2-4)^5[\frac{d}{dx}(3x+4)^4]

y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)

y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

5 0
2 years ago
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