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zimovet [89]
4 years ago
11

What is the explicit formula for this geometric sequence? 8, 4 2, 1

Mathematics
1 answer:
11Alexandr11 [23.1K]4 years ago
3 0

Answer:

C

Step-by-step explanation:

The standard form for the explicit formula of a geometric sequence is given by:

a_n=a\cdot(r)^{n-1}

Where a is the initial term, r is the common ratio, and n is the nth term.

Our sequence is: 8, 4, 2, 1...

So, we can see that our initial term or a is 8.

Each subsequent term is half of the previous one. So, our common ratio is 1/2.

Let's substitute 8 for a and 1/2 for r to acquire:

a_n=8\cdot(\frac{1}{2})^{n-1}

So, our answer is C.

And we're done!

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Solve 3^x − 2 = 3^7<br><br> A. 2<br> B. 5<br> C. 7<br> D. 9
Vikki [24]

Answer:

C) 7

Step-by-step explanation:

3^x−2=2187

Step 1: Add 2 to both sides.

3^x−2+2=2187+2

3^x=2189

Step 2: Solve Exponent.

3^x=2189

log(3x)=log(2189)        <<Take log of both sides

x*(log(3))=log(2189)

x= log(2189)/log(3)

x=7.000832

4 0
3 years ago
On a piece of paper, use a protractor to construct a triangle with angle measures of 40° and 60º.
andrew-mc [135]

Answer:

There are 180 degrees in a triangle so it is 80 degrees

4 0
2 years ago
Read 2 more answers
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
4 years ago
2. Point B is located at (-4,5). The midpoint of line segment BD is point c(-1,0). What are the coordinates
andreev551 [17]

Answer:D is 0,-5

Step-by-step explanation:

8 0
3 years ago
How do I complete this equation
Nesterboy [21]

Answer:

130°

Step-by-step explanation:

All the interior angles should add up to 540 degrees because it's a pentagon

∠T ≅∠S, so ∠T is also 115°

∠P and ∠R are both 90°

Add everything up and solve for ∠Q:

115 + 115 + 90 + 90 + m∠Q = 540

410 + m∠Q = 540

m∠Q = 130°

8 0
3 years ago
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