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ohaa [14]
4 years ago
8

What is the volume of the right prism? * 6 cm 4 cm 16 cm

Mathematics
2 answers:
zalisa [80]4 years ago
5 0

Answer:

6*4*16=384

Step-by-step explanation:

tigry1 [53]4 years ago
5 0

Answer:

V = 384 m^3

Step-by-step explanation:

V= 1/2a * c * h

you didnt say which is length, width, or height so idk if this is right

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What is the slope of a line that has a y-intercept but no x intercept
IRINA_888 [86]

Answer:

The slope of a line that has a y-intercept but no x-intercept will be zero.

Step-by-step explanation:

If the line has no x-intercept, then it never intersects the x-axis, so it must be parallel to the x-axis.

If a line does not have an x-intercept, it means it would never intersect the x-axis.

Thus, it must be parallel to the x-axis, meaning its slope will be zero. It would be just a horizontal line.

For example, y=9 is the line equation that does not have an x-intercept and its slope is zero.

Therefore, the slope of a line that has a y-intercept but no x-intercept will be zero.

7 0
3 years ago
Given that cosΘ = -square root 2/2 and that Θ lies in quadrant III, determine the value of sinΘ.
Reptile [31]

Answer:

  C) (square root 2)/2

Step-by-step explanation:

In quadrant III, the sine of an angle is positive. The value will be ...

  sin(Θ) = √(1 -cos(x)^2) = √(1 -(-√2/2)^2) = √(2/4)

  sin(Θ) = (√2)/2

6 0
2 years ago
Use the simple interest formula method to calculate the future value of an annuity with annual annuity payments of $1200 at 4% i
nikitadnepr [17]

Answer:

Step-by-step explanation:

A = $2,629.35
A = P + I where
P (principal) = $1,200.00
I (interest) = $1,429.35

8 0
2 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
What is the simplest form of 9/24, 14/24, 10/15, 10/12,18/27 and 10/15?
PSYCHO15rus [73]
S.F. of 9/24 = 3/8
S.F. of 14/24 = 7/12
S.F. of 10/15 = 2/3
S.F. of 10/12 = 5/6
S.F. of 18/27 = 2/3
S.F. of 10/15 = 2/3

Hope this helps!
8 0
3 years ago
Read 2 more answers
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