Subtract 11 from n then divide by 5
2 answers:
Answer:
Step-by-step explanation:
1) Subtract 11 from n to get You cannot find a solution for it because there is no value for n.
2) You divide that by 5 so you would just put n-11 over 5 to create a fraction that would look like
I am not sure if this is what you were asking but this is the most I can do for you with the information that you gave.
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Answer:
(a) A = (20mg)/(2^(t/30))
(b) 12.6mg
(c) 129.6years
Step-by-step explanation:
To calculate the amount remaining after a number of half-lives, n, we can make use of:
Where A = amount remaining
B = initial amount
(a) A = (20mg)/(2^(t/30))
(b) Mass after 20years
A = (20mg)/(2^(20/30)) ≈ 12.6mg
(c) After how long will only 1mg remain:
1mg = (20mg)/(2^(t/30))
Taking log of both sides we have:
Log(20) = (t/30)log(2)
t/30 = (log(20))/(log(2)) ≈ 4.3
t/30 = 4.3
t = 30 x 4.3 ≈ 129.6years.