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stiks02 [169]
3 years ago
11

A 95% confidence interval for the proportion of students achieving a reading achievement score that is above the standard set by

the teachers for a population of third grade students is (0.43, 0.49).
The margin of error of this interval is:

Group of answer choices

0.05

0.03

0.06

None of the above
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0
Answer:

0.03

Explanation:

First, you subtract the upper bound of the confidence interval by the lower bound of the confidence interval. Then, you divide that number by 2 to get the margin or error.

In this case: (0.49 - 0.43)/2 = 0.03
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Answer:

a) cblo

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Step-by-step explanation:

4 cans and 3 loaves=11.67

8 cans and 1 loaf= 12.89.

Set up equation:

x=cans

y=loaves

4x+3y=11.67\\8x+y=12.89 This is the answer for question A.

Multiply eq1 by 2:

8x+6y=23.34

Subtract eq3 by eq2:

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Substitute:

8x+2.09=12.89\\8x=10.8\\x=1.35

One can of soup and one loaf of bread=

1.35+2.09 or 3.44

So:

$3.44

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- 10 < x - 9
ANSWER
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Answer:

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