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3 years ago

An equation is shown. 2x-4y=8 solve the equation for x in terms of y

1 answer:

7 0

2x-4y=8

Add 4y to each side to separate the variables, since you want to solve for x let be on the left

2x=4y+8

Divide the entire equation by 2 to allow x to stand alone

x=2y+4

And I have to type some more so it will let me answer the question so here ya go

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What is the domain of the function shown in the graph below?

tigry1 [53]

Answer:

All except one interval [-2,8]

Step-by-step explanation:

Notice that the function, wich an hyperbola, has a vertical asymptote in both -2 and 8 and there is nothing between this two values.

So we will exclude what's between them out of the domain.

6 0

3 years ago

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Make a table for the following equations<br> y = 2x + 4

nekit [7.7K]

In order to make a table, we sample some x values (whichever we want), and we compute the expression for those value. Each x value will yield a unique y value.

If you need this table to graph the function, you'll only need two points, since this is a line, and having two points you just need to connect them.

Here are some samples, feel free to make more if you need to:

$f(x)=2x+4\implies f(0)=2\cdot 0 + 4 = 4$

$f(x)=2x+4\implies f(1)=2\cdot 1 + 4 = 6$

$f(x)=2x+4\implies f(2)=2\cdot 2 + 4 = 8$

$f(x)=2x+4\implies f(3)=2\cdot 3 + 4 = 10$

$f(x)=2x+4\implies f(4)=2\cdot 4 + 4 = 12$

So, we have the following table

$\begin{array}{c|c}0&4\\1&6\\2&8\\3&10\\4&12\end{array}$

4 0

3 years ago

I will give u brainiest if ur correct and your first correct.

marissa [1.9K]

The answer to the first part is 26 i think

Bc 6-10 theres 10 and 10-15 theres 16

3 0

3 years ago

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I don't know what's it asking me. what should I do?

Anton [14]

$n$ - a number
$n^2$ - its square
$n+n^2$ - the sum
$\leq$ - less than or equal
negative three - I don't have to explain this one, do I?

$n+n^2\leq-3$ - the sum of a number and its square is less than or equal negative three

6 0

3 years ago

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Solve and check the equation<br> 2(4-5x) = 2(3x+2)

Tasya [4]

ANSWER: 0,25
Ok done. Thank to me :>

3 0

2 years ago

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