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4 years ago

6

An equation is shown. 2x-4y=8 solve the equation for x in terms of y

1 answer:

horrorfan [7]4 years ago

7 0

2x-4y=8

Add 4y to each side to separate the variables, since you want to solve for x let be on the left

2x=4y+8

Divide the entire equation by 2 to allow x to stand alone

x=2y+4

And I have to type some more so it will let me answer the question so here ya go

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Joseph drives 125 miles in 25 hours. At the same rate how far will he be able to travel in 6 hours.

Murrr4er [49]

125 ÷ 25 is 5

5 ⋅ 6 is 30

Joseph will go 30 miles in 6 hours

The answer is 30.

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4 years ago

There is a bag filled with marbles: 5 red, 8 blue, 4 yellow, and 3 green.

likoan [24]

Answer:

Step-by-step explanation:

total marbles=5+8+4+3=20

when he is drawing without replacing means red marble is drawn from 20 marbles.

Blue marble is drawn from 19 marbles.

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3 years ago

F(x) = x + 2<br> g(x) = 3x^2 – 5<br> Find (f • g)(x).

Yakvenalex [24]

Answer: $3x^3+6x^2-5x-10$

Step-by-step explanation:

$\left(x+2\right)\left(3x^2-5\right)$

$x\cdot \:3x^2+x\left(-5\right)+2\cdot \:3x^2+2\left(-5\right)$

$=3x^3+6x^2-5x-10$

7 0

3 years ago

25 POINTS AVAILABLE

myrzilka [38]

Answer:

$\large\boxed{1.\ (-3, 0),\ r = 3}\\\boxed{2.\ (x+4)^2+(y-3)^2=36}\\\boxed{3.\ (x-2)^2+(y-1)^2=(\sqrt{34})^2}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

1. We have the equation:

$(x+3)^2+y^2=9\\\\(x-(-3))^2+(y-0)^2=3^2$

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2. We have the center (-4, 3) and the radius r = 6. Substitute:

$(x-(-4))^2+(y-3)^2=6^2\\\\(x+4)^2+(y-3)^2=36$

3. We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

7 0

3 years ago

What is the diameter of the circle 18in?

avanturin [10]

56.57 that’s the answer

7 0

3 years ago