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3 years ago

30 pts please answer

Mathematics

2 answers:

ddd [48]3 years ago

4 0

I think it's d but can't be sure

qaws [65]3 years ago

3 0

Answer:

The answer is D

Step-by-step explanation:

I hope this helps

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A tube of toothpaste is marked $3.92 for 8 ounces. What is the price per ounce?

Alisiya [41]

Find one ounce $3.92/8=$0.49
$0.49 per ounce

5 0

3 years ago

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Use the graph of the function y = 4x to answer the following questions.

Sav [38]

Hello from MrBillDoesMath!

Answer:

For y = 4x, the domain of the function is all real numbers. This can be indicated as ( -infinity, infinity),

...later part of question:...

..."because an exponent can be any real"

exponent? !!!

Did you mean y = 4^x ? In this case the domain of y is all real numbers ann the range is (0, infinity), where the value 0 is not included in the range.

Thank you,

MrB

4 0

3 years ago

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Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago

The measure of two angles of a triangle are 56 degrees and 39 degrees.find the measure of the third angle

8_murik_8 [283]

Answer:

Step-by-step explanation:

Angle 1: 56

Angle 2: 39

56+39=95

A triangles angles add up to 180 degrees.

180-95=85

Angle 3:85

3 0

3 years ago

The length of a rectangular field is 7 m less than 4 times the width. The perimeter is 136 m. Find the width and the length

Helga [31]

Answer:

Step-by-step explanation:

Represent the width by W. Then, "The length of a rectangular field is 7 m less than 4 times the width" expressed symbolically is

L = 4W - 7 (dimensions in meters)

Recall that the perimeter formula in this case is P = 2L + 2W, and recognize that the perimeter value is 136 m. After substituting 4W - 7 for L, we get:

136 m = 2(4W - 7) + 2W, or

136 = 8W - 14 + 2W, or

150 = 10W These three equations are equivalent mathematical statements.

150 = 10W reduces to W = 15 (meters).

Part A: the independent variable is W, the width of the field.

Part B: The mathematical statement is 136 m = 2(4W - 7) + 2W, which after algebraic manipulation becomes 150 = 10W.

Part C: The above equation can be solved for W: W = 15 meters. This is the value of the independent variable.

6 0

2 years ago