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2 years ago

In 2 hours reggie drives 220 kilometers how many kilometers can he drive in 6 hours

Mathematics

2 answers:

Sav [38]2 years ago

7 0

The answer to this question would be 660

Daniel [21]2 years ago

3 0

Answer:

220 divided by 2 equals 110

So just do 110 times 6 which equals 660

Step-by-step explanation:

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A bag contains yellow marbles and blue marbles, 73 in total. The number of yellow marbles is 7 more than 5 times the number of b

Roman55 [17]

Answer:

number of yellow marbles=62.

Step-by-step explanation:

It is given that in a bag there are yellow marbles and blue marbles and the total number of marbles=73.

Let the number of Blue marbles=x, then according to the question, number of yellow marbles will be =5x+7.

Now, Total number of marbles= number of yellow marbles+number of blue marbles.

⇒73=x+5x+7

⇒73-7=6x

⇒66=6x

⇒x=11

Therefore, numberof blue marbles=x=11 and

number of yellow marbles=5x+7=5(11)+7=55+7=62.

8 0

3 years ago

What number is 30% of 90

marta [7]

Answer:

it is 27 as you multiply .30 times 90

3 0

3 years ago

Read 2 more answers

One leg of a right triangle has length 7. The lengths of the other two sides are whole numbers. The length of the other leg is _

Gekata [30.6K]

It should be 7, 24 and 25

8 0

3 years ago

Can you answer problem 11?

In-s [12.5K]

Answer:

well you didn't show problem 11 but here is a pretty photo of Port orford Oregon

7 0

2 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

3 years ago