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shusha [124]
4 years ago
12

30 points to whoever can answer this please!

Mathematics
2 answers:
Anastasy [175]4 years ago
8 0

Answer:

y=6sin3(x+1)

Step-by-step explanation:

qwelly [4]4 years ago
4 0
A common sinusoidal function is:

y = asin(bx)

so,always amplitude is a, so a=6

and we know period is:

p = \frac{ |b| }{2\pi}

so

\frac{ |b| }{2\pi} = \frac{2\pi}{3}

b = + or - \frac{4 {\pi}^{2} }{3}

and we have 2 equations that while we can consider which is appropriate ,to have its graph!

6 \sin( \frac{4 {\pi}^{2} }{3}x )
and when you want to shift it 1 unit left we have:
6 \sin( \frac{4 {\pi}^{2} }{3}x +1)
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Dan sells beaded necklaces. Each large necklace sells for $5.30 and each small necklace sells $3.90. How much will he earn from
ycow [4]
5.30 for 1 large and 19.50 for 5 smalls

5 0
4 years ago
Read 2 more answers
Write the equation of a parabola with focus at (1,-4) and a directrix at X=2
konstantin123 [22]

Answer:

The equation of a parabola is

x =  \frac{1}{4(f - h)} (y - k) ^{2}  + h

Step-by-step explanation:

(h,k) is the vertex and (f,k) is the focus.

Thus, f = 1, k = −4.

The distance from the focus to the vertex is equal to the distance from the vertex to the directrix: f - h = h - 2.

Solving the system, we get h = 3/2, k = -4, f = 1.

The standard form is:

x =  -  \frac{y ^{2} }{2}  - 4y -  \frac{13}{2}

The general form is:

2x +  {y}^{2}  + 8y + 13 = 0

The vertex form is:

x =  -  \frac{(y + 4) ^{2} }{2}  +  \frac{3}{2}

The axis of symmetry is the line perpendicular to the directrix that passes through the vertex and the focus: y = -4.

The focal length is the distance between the focus and the vertex: 1/2.

The focal parameter is the distance between the focus and the directrix: 1.

The latus rectum is parallel to the directrix and passes through the focus: x = 1.

The length of the latus rectum is four times the distance between the vertex and the focus: 2.

The eccentricity of a parabola is always 1.

The x-intercepts can be found by setting y = 0 in the equation and solving for x.

x-intercept:

( -  \frac{13}{2}  \: ,0)

The y-intercepts can be found by setting x = 0 in the equation and solving for y.

y-intercepts:

(0, - 4 -  \sqrt{3)}

(0, - 4 +  \sqrt{3)}

3 0
3 years ago
What are the coordinates of the image of the point (4, 2) after a dilation with a center of (0, 0) and a scale factor of 2? A. (
frez [133]

Answer:

Option D (8,4)

Step-by-step explanation:

we know that

The dilation centered at the origin  (0,0) is very simple. To find out the image point multiply the scale factor to the x  and  y-coordinates of the pre-image point.

so

(2*4,2*2) -----> (8,4)

8 0
4 years ago
Can u please explain how to do this?
mafiozo [28]
B is the correct answer. 
8 x 35 = 280
5 0
4 years ago
Read 2 more answers
Please no links or files
Nana76 [90]

Answer:

A

Step-by-step explanation:

2.25 > 1 5/6 > 1/2 > -1.5 > -3 1/4

6 0
2 years ago
Read 2 more answers
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