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marusya05 [52]
3 years ago
5

Write an if-else statement that displays 'Speed is normal' if the speed variable is within the range of 24 to 56. If the speed v

ariable’s value is outside this range, display 'Speed is abnormal'.
Computers and Technology
1 answer:
kari74 [83]3 years ago
4 0

Answer:

import java.util.Scanner;

public class Speed{

int speed;

public Speed(int speed){

this.speed = speed;

}

public void checkSpeed(){

if(speed >= 24 || speed <= 56){

System.out.println("Speed is normal");

}

else

System.out.println("Speed is abnormal");

}

public static void main(String...args){

Scanner input = new Scanner(System.in);

int userSpeed = 0;

System.out.println("Enter a speed: ");

userSpeed = input.nextInt();

Speed obj1 = new Speed(userSpeed)

obj1.checkSpeed();

}

Explanation:

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You receive an offer for a credit card that can be use to accrue points that
Jlenok [28]

Answer: (C) A special service for current customers

Explanation:

  The CRM is the customer relationship management that typically use by the banks for providing special type of services to the current customer. This is the way to attract various types of users or customers by providing some special type of offers.

According to the question, bank provide the credit card offers to the customer on the airline tickets so, it is beneficial for both the customer and for the bank as well.

3 0
3 years ago
Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.
Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

v = \frac{(xf-xo)}{(t-to)}

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

t =\frac{xf}{v}  =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.

⇒ t = 8.7*10⁻⁴ sec.

4 0
3 years ago
How do you get a code in C to count down from 5??
Valentin [98]

Answer:

This is what the code should do:

“Lift off in T minus

5

4

3

2

1

Blast-off!”

When I run it, it just keeps printing ''Sum = 5'' forever.

Explanation:

Code:

int main(void) {

int sum = 5;  

int i;      

printf("Lift off in T minus\n");

for (i = 0; i < 5; i=i+i) {

   sum = sum - i;  

   printf("sum = %d\n",sum);  

}  

printf("Blast-off",sum);  

return 0;

5 0
3 years ago
What is the LER for a rectangular wing with a span of 0.225m and a chord of 0.045m
ch4aika [34]

Calculate LER for a rectangular wing with a span of 0.225m and a chord of 0.045m. The weight of the glider is 0.0500 Newtons. (Note: the wing span is the width of the wing and is measured from wing tip to wing tip, or perpendicular to the fuselage. The wing chord is the length of the wing measured parallel or along the length of the fuselage.)

Answer:

Area of rectangular wing = span × chord = 0.225×0.045= 0.010125m2

LER = Area/weight = 0.010125/0.0500 = 0.2025

4 0
3 years ago
Brainless is one the way if you help
V125BC [204]

Answer:

1. x - 6

2. p - ? = 7

i chose these equations because

a number - 6 = the weight of your backpack.

p - an unknown number without a substitute variable = slices of bread left.

3 0
2 years ago
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