Answer:
B = (5,4), C = (-5, -4), D = (5, -4), A = (-5, 4)
Step-by-step explanation:
look at x axis first (horizontal), then y axis (vertical)
You can use the slope formula y2-y1/x2-x1 to find slope, the answer is D
Answer:
n>-13
Step-by-step explanation:
so you subtract 4 from -9 then since your not multiplying or divinding by a negative you don't flip the sign
Answer:
y= -2/3x-2
Step-by-step explanation:
Since we have a point and a slope, we can use the point slope formula
m is the slope. In this case, m is -2/3
y1 is the y coordinate of the point. In this case, it is -2
x1 is the x coordinate. In this case it is 0.
We can substitute these values into the formula
y- -2= -2/3(x-0)
Distribute -2/3
y+2 = -2/3*x + -2/3*0
y+2= -2/3x+0
Subtract 2 from both sides. We want to get y by itself. This is because we want our line to be in y=mx+b form.
y+2-2= -2/3x+0-2
y= -2/3x -2
It's not obvious here, but you're being asked to find a linear equation for the velocity of the car, given two points on the line that represents this velocity.
Find the slope of the line segment that connects the points (3 hr, 51 km/hr) and (5 hr, 59 km/hr). Graph this line. Where does this line intersect the y-axis? Find the y-value; it's your "y-intercept," b.
Now write the equation: velocity = (slope of line)*t + b
The units of measurement of "slope of line" must be "km per hour squared," and those of the "y-intercept" must be "km per hour."
Part B: Start with the y-intercept (calculated above). Plot it on the vertical axis of your graph. Now label the horizontal axis in hours: {0, 1, 2, 3, 4, 5, 6}. Draw a vertical line through t=6 hours. It will intercept both the horiz. axis and the sloping line representing the velocity as a function of time. Show only the part of the graph that extends from t=0 hours to t=6 hours.
