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Ipatiy [6.2K]
3 years ago
10

Which function has an asymptote at x= 39

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
4 0

Answer:

The correct answer is b. f(x) = log7(x-39)


LekaFEV [45]3 years ago
3 0

Answer:

option B : f(x)= log_7(x-39)

Step-by-step explanation:

(a) f(x) = 7^{x-39}

For exponential function , there is no vertical asymptotes

General form of exponential function is

f(x) = n^{ax-b}+k

f(x) = 7^{x-39}

In the given f(x) the value of k =0

So horizontal asymptote is y=0

(b) lets check with option

f(x)= log_7(x-39)

To find vertical asymptote we set the argument of log =0  and solve for x

Argument of log is x-39

x-39=0 so x=39

Hence vertical asymptote at x=39


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Find the equation of the line passing through points (-4,2) and (1,-6)
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Answer:

y + 6 = (-8/5)(x - 1) in point-slope form

Step-by-step explanation:

Moving from the 1st point to the first, we see that x (the 'run') increases by 5 from -4 to 1, and y (the 'rise') decreases by 8.  Thus, the slope of the line through these two points is m = rise / run = -8/5

Now we have two points on the line, plus the slope.  Let's write out the point-slope formula for the equation of a straight line:

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Here, using the point (1, -6), we obtain:

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Sarah has a 6 cup bag of rice. If a serving is ¾ of a cup, how many servings does Sarah have?
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Answer:

17.9 units is the answer

Step-by-step explanation:

points are (-7,-2) and (9,6)

Pythagorean theorem can be written as,

d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\\\d=\sqrt{9-(-7))^2 + (6-(-2))^2}\\\\d=\sqrt{(16)^2+(8)^2} \\\\d=\sqrt{256+64} \\\\d=\sqrt{320} \\\\d=17.88

Rounding off,

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