Question

Which function has an asymptote at x= 39

Answer 1

Answer:

The correct answer is b. f(x) = log7(x-39)

Answer 2

Answer:

option B : $f(x)= log_7(x-39)$

Step-by-step explanation:

(a) $f(x) = 7^{x-39}$

For exponential function , there is no vertical asymptotes

General form of exponential function is

$f(x) = n^{ax-b}+k$

$f(x) = 7^{x-39}$

In the given f(x) the value of k =0

So horizontal asymptote is y=0

(b) lets check with option

$f(x)= log_7(x-39)$

To find vertical asymptote we set the argument of log =0  and solve for x

Argument of log is x-39

x-39=0 so x=39

Hence vertical asymptote at x=39