Question

Find the difference of (-3-3i)-(6-5i). Show your work.

Answer 1

Answer:-9+2I

Step-by-step explanation: MUTIPLYING THE SECOND BRACKET BY THE NEGATIVE SIGN.

(-3-3I)(-6+5I)

COLLECTING LIKE TERMS

(-3-6)(-3I+5I)

=-9+2I

Answer 2

Answer:

The difference is:

$-9+2i$

Step-by-step explanation:

We have the subtraction of two complex numbers.

$(-3-3i)-(6-5i)$

To solve the operation, the product of:

$-(6-5i)$

$-6 +5i$

Now add the two expressions. Add real numbers with real numbers and complexes with complex numbers

$-3-3i-6 +5i$

$-3-6 +5i-3i$

$-9+2i$

The difference is:

$-9+2i$