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SVEN [57.7K]
3 years ago
9

Find the difference of (-3-3i)-(6-5i). Show your work.

Mathematics
2 answers:
QveST [7]3 years ago
7 0

Answer:-9+2I

Step-by-step explanation: MUTIPLYING THE SECOND BRACKET BY THE NEGATIVE SIGN.

(-3-3I)(-6+5I)

COLLECTING LIKE TERMS

(-3-6)(-3I+5I)

=-9+2I

sweet [91]3 years ago
6 0

Answer:

The difference is:

-9+2i

Step-by-step explanation:

We have the subtraction of two complex numbers.

(-3-3i)-(6-5i)

To solve the operation, the product of:

-(6-5i)

-6 +5i

Now add the two expressions. Add real numbers with real numbers and complexes with complex numbers

-3-3i-6 +5i

-3-6 +5i-3i

-9+2i

The difference is:

-9+2i

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2 years ago
Which expression is equivalent to 4^-5 • 3^-5 ?
valkas [14]

The expression equivalent to 4^-5 • 3^-5  is 12^-5

<h3>What are equivalent expressions?</h3>

Equivalent expressions are simply known as expressions with the same solution but different arrangement.

Given the index expressions;

4^-5 • 3^-5

Using the exponent rule, the two values are have different bases but the same exponent and thus, we multiply the bases and leave the exponents the same way.

This can be written as;

4(3) ^ -5

expand the bracket

12^-5

Thus, the expression equivalent to 4^-5 • 3^-5  is 12^-5

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1 year ago
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Step-by-step explanation:

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3 years ago
Which answer choice states the range of the following
ankoles [38]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.

Remember that for any relation, we have a set A that matches the the domain (also called the set of inputs) of the function and the set B that contains the range (also called the set of outputs).

Suppose our relation is:

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So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:

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3 years ago
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