The distance traveled by first car is 50t + 100.
The distance traveled by second car is 70t.
The distance between the two cars after time, t is d = 100 - 20t.
The ratio of the distance traveled by the cars is (70t) / (50t + 100).
<h3>
Distance traveled by each vehicle is calculated as follows;</h3>
The distance traveled by each vehicle at the given time is calculated as follows;
<h3>Distance traveled by first car</h3>
D₁ = speed x time
D₁ = 50(t + 2)
D₁ = 50t + 100
<h3>Distance traveled by the second car</h3>
D₂ = 70t
<h3>Distance between the two cars after time, t</h3>
d = D₁ - D₂
d = (50t + 100) - 70t
d = 100 - 20t
<h3>Ratio of the distance traveled by the cars</h3>
D₂/D₁ = (70t) / (50t + 100)
Learn more about distance traveled by a vehicle here: brainly.com/question/6504879
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Answer:
See the attachment photo!
Answer:
MN = 34, x = 7
Step-by-step explanation:
look at the file, cut off numbers are:
37
37
36
Answer:
let W and R represent white toothpaste and red toothpaste represently
n(W)=143
n(R)=135
n(WnR)=70
n( WuR)=?
Now,
n(WuR)=n(W)+n(R)_n(WnR)
=143+135_70
=208
that's all don't forget to write therefore.
11.
(87+91+86+x)/4=90.
x=96.
13.
50×y > 130.
the lowest number could be 3, because 50×2=120, which is less than 130.
