Question

What are the solutions of the following system

Answer 1

Answer:

(-6, 312), (6, 312)

Step-by-step explanation:

$\left\{\begin{array}{ccc}10x^2-y=48\\2y=16x^2+48&\text{subtracy}\ 16x^2\ \text{from both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}10x^2-y=48\\-16x^2+2y=48&\text{divide both sides by 2}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}10x^2-y=48\\-8x^2+y=24\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x^2=72\qquad\text{divide both sides by 2}\\.\qquad x^2=36\to x=\pm\sqrt{36}\\.\qquad x=\pm6\\\\\text{Put the values of}\ x\ \text{to the second equation}$

$2y=16(\pm6)^2+48\\\\2y=16(36)+48\\2y=576+48\\2y=624\qquad\text{divide both sides by 2}\\y=312$

Answer 2

Answer:

c i think

Step-by-step explanation: