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3 years ago

These tables of values represent continuous functions. In which table do the values represent an exponential function?

Mathematics

1 answer:

denis-greek [22]3 years ago

7 0

Answer:

Option C

Step-by-step explanation:

In this case, an exponential function is a function that has common ratio whereas it is called a linear function if it has common difference.

Option A:

Since the values of y in the given table have different ratio but common difference, therefore it is not a a linear and not an exponential function. Option A is is not correct.

Option B:

Since the values of y in the given table have different ratio but common difference, therefore it is not a a linear and not an exponential function. Option B is not correct.

In option C.

Since the given values of y in the table have a common ratio, it is said to be an exponential function.

Option C is correct.

In option D.

Since the values of y in the given table have different ratio but common difference, therefore it is not a a linear and not an exponential function. Option D is incorrect.

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Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

1 computer : 1 worker : inventory 150 items per hour
1 computer : 2 workers : inventory 200 items per hour
1 computer : 3 workers : inventory 220 items per hour
1 computer : 4+ workers : fewer than 235 items per hour
Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

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-The variable production factor is the number of workers assigned per one computer.

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$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03$

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925$

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98$

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

$Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05$

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

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4 years ago

At midnight the temperature was 30°F by 6 o'clock in the morning it was dropped 15° & by noon increased by 22° what was the

Mila [183]

Answer: 37°F

let me know if this is wrong

Step-by-step explanation:

30-15=15

15+22=37

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3 years ago

Point-Slope Form *See photo*

Ne4ueva [31]

Answer:

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2 years ago

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svlad2 [7]

Answer:

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