Given:
• Total number of cans collected = 150
,
• Percent of cans that were soda = 58%
Let's find the number of other cans he collected.
To find the number of other cans, since the percent of soda is 58%, let's find the pecent of other cans.
Percent of other cans = 100% - 58% = 42%
The percent of other cans collected was 42%.
Now, to find the number of other cans collected, let's find 42% of the total number of cans collected 150.
We have:
Therefore, the number of other cans collected is 63 cans.
ANSWER:
63 cans
(n + 7)2 = n - 1
2n +14 = n - 1
2n - n +14 = n - n - 1
n + 14 -14 = -1 - 14
n = -15
(-15 + 7)2 = -15 - 1
(-8)2 = -16
-16 = -16
Answer:
i dont know for sure but it says possible order pairs
6,12
Answer:
Step-by-step explanation:
Since the results for the standardized test are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = test reults
µ = mean score
σ = standard deviation
From the information given,
µ = 1700 points
σ = 75 points
We want to the probability that a student will score more than 1700 points. This is expressed as
P(x > 1700) = 1 - P(x ≤ 1700)
For x = 1700,
z = (1700 - 1700)/75 = 0/75 = 0
Looking at the normal distribution table, the probability corresponding to the z score is 0.5
P(x > 1700) = 1 - 0.5 = 0.5
8x - 2y = -8
-5x + 2y = -1
3x = -9
x = -3
