Answer:
See explanation
Explanation:
The atoms of metals have fewer valence electrons than the atoms of metals and metalloids.
Atoms of metals have only very few valence electrons in their outermost shells hence they donate electrons during bonding. However, atoms of nonmetals have more electrons in their outermost shells and rather accept electrons during bonding. The atoms of metalloids just have a number of valence electrons that are intermediate between those of metals and nonmetals and mostly share electrons in covalent bonds.
Similarly, atoms of metallic elements differ from each other in the number of valence electrons present in the valence shell of the atom of each element. For instance, sodium has one electron in the valence shell of its atom while aluminium has three electrons in the valence shell of its atom.
Answer:
the molecules move more quickly and their average kinetic energy decreases :D
Explanation:
Explanation:
The given reaction will be as follows.
So, equilibrium constant for this equation will be as follows.
As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.
=
= 0.173
Thus, we can conclude that equilibrium constant for the given reaction is 0.173.
Answer:
The first five elements of the periodic table are:- hydrogen, helium, lithium, beryllium, boron
Explanation:
atomic number- it is represented by the letter Z. It is basically the total number of protons present in each atom's nucleus of that element.
atomic mass- is the mass of a single atom present in the element.
electrons and protons- they are negatively and positively charged particles found in the nucleus of the atom respectively.
neutrons- they have no or zero charge and weigh more than protons.
element | atomic number | atomic mass | electrons | protons | neutrons
hydrogen (H)- 1 | 1.008 | 1 | 1 | 0
helium (He) - 2 | 4.0026 | 2 | 2 | 2
Lithium (Li) - 3 | 6.94 | 3 | 3 | 4
beryllium (Be) - 4 | 9.0122 | 4 | 4 | 5
Boron ( B) - 5 | 10.81 | 5 | 5 | 6
Average atomic mass of an element is a sum of the product of the isotope mass and its relative abundance.
For example: Chlorine has 2 isotopes with the following abundances
Cl(35): Atomic mass = 34.9688 amu; Abundance = 75.78%
Cl(37): Atomic mass = 36.9659 amu; Abundance = 24.22 %
Average atomic mass of Cl = 34.9688(0.7578) + 36.9659(0.2422) =
= 26.4993 + 8.9531 = 35.4524 amu
Thus, the term “ average atomic mass “ is a <u>weighted</u> average so it is calculated differently from a normal average