Answer:
Molarity of HCl=0.026092M
Explanation:
The equation for the reaction is;
HCl + NaOH ⇒ NaCl + H2O
Using the formular, 
..........equ1
where
is the concentration of Acid,
is volume of acid
is concentration of the base
is volume of the base
nA is the number of moles of Acid
nB is number of moles of base
nA = 1, nB=1 , 
, 
, 
we will input these values into equation1 to solve for
Copper(I) compounds in aqueous solutions are unstable and disproportionate:
Cu₂SO₄ = Cu + CuSO₄
Necessary for dissolution of non-aqueous solvent.
M(Cu₂SO₄)=223.16 g/mol
m(Cu₂SO₄)=14.1 g
v=0.250 L
n(Cu₂SO₄)=m(Cu₂SO₄)/M(Cu₂SO₄)
c=n(Cu₂SO₄)/v=m(Cu₂SO₄)/(vM(Cu₂SO₄))
c=14.1/(0.250*223.16)=0.253 mol/L
0.253 M
1st one is Science and the 2nd one is Bias
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Feso3 compound name
Iron(II) Sulfite FeSO3 Molecular Weight
Hope this helps!
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