Answer:
In a long channel MOSFET, the width of the pinch-off region is assumed small relative to the length of the channel. Thus, neither the length nor the voltage across the inversion layer change beyond the pinch-off, resulting in a drain current independent of drain bias. Consequently, the drain current saturates.
Explanation:
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Give the positional isomers of 2 halopropane
(CH3)2CH
answer:
is in file download it
Answer:
★ v = d/t
★ v = 90/30
★ v =3
<u>Acc</u><u> </u><u>to</u><u> </u><u>question</u>
★ momentum = mass * velocity
★ m = 25×3
★ m = 75kgm/s
Hope it help
Answer:
P2= 125.26 Kpa
Explanation:
V1= 489.6 ml=0.4896L
V2= 750 ml= 0.750L
V1= 180 KPa= 180000 Pa
P2= ?
T1= 10 = 10 + 273.15 = 283.15K
T2= 28.7+273.15= 301.85K
180000Pa* 0.4896L/ 283.15K * 301.85K/0.75L
P2= 12526.28553
P2= 125.26 KPa
Your answer would be C. Alpha decay involves the ejection of 2 protons and 2 neutrons from the nucleus for a total of 4 amu lost. This form of decay is most common in heavy elements.