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viva [34]
3 years ago
10

How can you use the double number line diagram to find what percent 240 is of 300​?

Mathematics
2 answers:
kotykmax [81]3 years ago
7 0

Answer:

It is 80

Step-by-step explanation:

Percentage Calculator: 240 is what percent of 300? = 80.

wlad13 [49]3 years ago
6 0

Answer: 80

Step-by-step explanation:

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Let p be the plane in space that intersects the x-axis at −5, the y-axis at −2, and the z-axis at 5. Find a vector v¯¯¯ that is
Lana71 [14]

Let P be the plane that intersects

  • x-axis at point (-5,0,0);
  • y-axis at point (0,-2,0);
  • z-axis at point (0,0,5).

Write the equation of the plane P:

\left|\begin{array}{ccc}x-(-5)&y-0&z-0\\0-(-5)&-2-0&0-0\\0-(-5)&0-0&5-0\end{array}\right|=0\Rightarrow \left|\begin{array}{ccc}x+5&y&z\\5&-2&0\\5&0&5\end{array}\right|=0.

Then

-10(x+5)+10z-25y=0,\\ \\2(x+5)-2z+5y=0,\\ \\2x+5y-2z=-10.

The coefficients at variables x, y and z are the coordinates of perpendicular vector to the plane. Thus

\vec{v}=(2,5,-2)\perp P.

Answer: \vec{v}=(2,5,-2).

7 0
3 years ago
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
3 years ago
X^100+1 divide by x+1​
timofeeve [1]

Answer:

x=-1

Step-by-step explanation:

\frac{x ^{100} + 1 }{x + 1}

x + 1 = 0

x =  - 1

7 0
2 years ago
How can this product be simplified 8p(-2p^2+6p-2)
Nikitich [7]

Answer:

-16p³ + 48p² - 16p

Explanation:

In order to simplify the given expression, we need to multiplied 8p with (-2p²+6p-2)

8p*(-2p²+6p-2)

we need to distribute 8p over the brackets or parenthesis.

=8p*(-2p²) + 8p*(6p) + 8p*(-2)

= 8*(-2)*p*p² + 8*6p*p + 8*(-2)* p

= -16p³ + 48p² - 16p

We can't simplify it more, so that's the final answer.

I hope it's help.





8 0
3 years ago
Read 2 more answers
Solve for x.
Daniel [21]

Answer:

x=-\frac{9}{4} \\ or \:\\x = -2\frac{1}{4}

Step-by-step explanation:

-2 (x + 1/4)+1=5\\\\-2\left(x+\frac{1}{4}\right)+1=5\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\\\-2\left(x+\frac{1}{4}\right)+1-1=5-1\\\\Simplify\\-2\left(x+\frac{1}{4}\right)=4\\\\\mathrm{Divide\:both\:sides\:by\:}-2\\\frac{-2\left(x+\frac{1}{4}\right)}{-2}=\frac{4}{-2}\\\\Simplify\\x+\frac{1}{4}=-2\\\\\mathrm{Subtract\:}\frac{1}{4}\mathrm{\:from\:both\:sides}\\\\x+\frac{1}{4}-\frac{1}{4}=-2-\frac{1}{4}\\\\Simplify\\x=-\frac{9}{4}\\\\x = -2\frac{1}{4}

4 0
3 years ago
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