Standard quadratic equation .. y = a x^2 + b x + c
<span>parabola 'a' not equal to zero </span>
<span>a<0 parabola opens downward </span>
<span>a>0 parabola opens upward </span>
<span>when |a| >>0 the parabola is narrower </span>
<span>when |a| is close to zero , the parabola is flatter </span>
<span>when the constant is varied it only effects the vertical position of the parabola , the shape remains the same</span>
Step-by-step explanation:
blur po yung pictures. ulitin mo nalang
For the 1st one we need to solve x. x-y=2 step1: x-y+y=2+y answer: x=y+2
YEAH OFC SHAWTY!
- so for A its -4^11 because if the powers have the same base and they are being multiplied you add the powers
- For B its the same idea, they have the same base, and are being multiplied so you add the powers- 13^9
- For C its similar, you have the same base, but since its Dividing, you subtract the powers. So, 9^5
- for D you pretend like the denominator has a power of 1 and subtract. So its -24^5-24^1 which hopefully puts it into perspective of being -24^4 becuase we subtracted the powers
I cant do 2 right now, but i will in a minute
<u>And for 3 his mistake is that they arent the same bases so he cant add the powers, he should have converted them to the same base first. </u>
M= y2 - y1/ x2 - x1
m= 9-9/-2-2
m= 0/-4
m= 0
The slope is 0
