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3 years ago

6

A counting number is a multiple of 13 and is also divisible by 4 and 6. What is the smallest number that satisfies these conditi

ons?

1 answer:

ASHA 777 [7]3 years ago

8 0

Answer:

39

Step-by-step explanation:

39 is a multiple of 13. 13,26,39.

3+9= 12 which is an even which works both for 6 and 4. 4,8,12. 6,12

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This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

<u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
<u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
<u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

$\bold{\underline{ Let's \: Begin}}$

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

<u>Now</u><u>, </u>

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

3 years ago

David is making a wall out of bricks. Each brick is 2/3 foot long. There are 20 bricks lined up end to end to make the wall. Wha

Law Incorporation [45]

The total length of wall is 160 inches

<em><u>Solution:</u></em>

Given that,

$Length\ of\ each\ brick = \frac{2}{3}\ foot$

1 feet = 12 inches

Therefore,

$Length\ of\ each\ brick = \frac{2}{3} \times 12\ inches = 8\ inches$

There are 20 bricks lined up end to end to make the wall

<em><u>To find: Total length of wall in inches</u></em>

$Total\ length\ of\ wall = \text{length of each brick } \times \text{ total number of bricks}$

Thus we get,

$Total\ length\ of\ wall = 8 \times 20\\\\Total\ length\ of\ wall = 160\ inches$

Thus total length of wall is 160 inches

8 0

3 years ago

K/2+1/2=3<br> what is k?

Ann [662]

Answer:

k = 5

Step-by-step explanation:

k/2+1/2=3

Multiply each side by 2 to get rid of fractions

2(k/2+1/2)=3*2

k+1 = 6

Subtract 1 from each side to isolate k

k+1-1 = 6-1

k = 5

4 0

3 years ago

Which of the following is not true for a firm in perfect competition? Profit equals total revenue minus total cost. Average reve

kotegsom [21]

Answer: Second option is not true for a firm in perfect competition.

Step-by-step explanation:

We know that

In perfect competition, number of buyers and sellers are in large number, free entry and exit of firms, it sells homogenous products and can't earn abnormal profit.

In this competition, "Firm is the price taker, industry is the price maker".

and AR = MR as there is constant price fixed by the industry.

Hence, Second option is not true for a firm in perfect competition.

4 0

3 years ago

Tell whether it’s arithmetic or not reasoning 12,6,0,-6,-12

jekas [21]

Answer:

Yes this is an arithmetic sequence.

Step-by-step explanation:

12 , 6 , 0 , -6, -12

Difference = 2nd term - first term = 6 - 16 = -6

It is an arithmetic sequence and each term is got by adding (-6)

6 0

3 years ago