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Softa [21]
3 years ago
13

Why are microdeletions and microinsertions difficult to diagnosis using karyotyping?

Biology
2 answers:
Harman [31]3 years ago
8 0
Because only the chromosomes can be seen in a karyotype, and microdeletions or insertions are mutations at the molecular level, it is virtually impossible to detect such mutations at the chromosomal level. 
MrRa [10]3 years ago
7 0

Answer & explanation:

Mutations that occur by microinsertions or microdeletions (usually a pair of nitrogenous bases) can result in a change in the reading phase of the gene, completely modifying its translation into a particular protein.

Microinsertions are responsible for inserting a nucleotide into the DNA sequence, while microdeletions remove a nucleotide from the DNA sequence.

Diagnosing microdeletions or microinserts is highly difficult and requires highly skilled professionals, since many of the detected changes represent variations in copy number without clinical significance or of unknown clinical significance.

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Labrador retrievers may be black, brown, or golden in color. Although each color may breed true, many different outcomes occur i
Leto [7]

Answer:

For black:

  • AABB
  • AaBB
  • AaBb
  • AABb

For brown:

  • AAbb
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For golden:

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Explanation:

This question explains the phenomenon of epistasis. Epistasis encompasses the concept where one gene is dominant in such a way that it completely masks the effect of any other gene present. Here, black is said to be the epistatic gene considering the abundance in its appearance. The ratio of 9:3:4 can be seen in cross 8 which makes this question an example of recessive epistasis. Recessive epistasis occurs when alleles of one locus mask the appearance of alleles, both dominant and recessive, on the other locus. Recessive epistasis is also known as supplementary epistasis.

5 0
3 years ago
Why do vultures wait for there prey
RSB [31]

Answer:

A vulture attacks weak prey. They hunt by sight, so they often "watch over" the prey until it is ready, by their standards. ... Sometimes vultures wait for a larger feeder to attack the meat first, so that the meat is perfect for eating.

7 0
3 years ago
Read 2 more answers
The frequency of an allele in a population of manatees is 0.15. If the population is at Hardy-Weinberg for this locus, what numb
g100num [7]

Answer: C) 13.5

Explanation:

Given that the frequency of an allele in a manatee population is 0.15 and said population is at Hard-Weinberg (a well-known equation usually used to calculating processes regarding allele and genotype frequencies), the correct number of 600 individuals that should be homozygous for the allele is <u>13.5 individuals.</u>

3 0
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In this activity, you will explore how DNA microarrays are being used as a tool for studying-and possibly treating--cancer 1 2 3
sineoko [7]

Microarray data attached

Answer:

B, D, E are consistent with the data in the microarray

Explanation:

A) False, if you look at the microarray graph, Gene K is red on the right side of the graph (where patients in group II are) and generally more blue on the left side where group I patients are, meaning it is less expressed

B) This is true, look for example at gene F, individual 3 expresses it strongly, whereas individuals 6 and 7 are quite low.

C) No - microarray data looks at the expression of genes, not the genes themselves.

D) Yes, you can see that generally, genes B-Q are highly expressed in group II patients but not group I. In contrast, genes F-U are not expressed in group II but more expressed in group I.

E) Yes, although the data is not always consistent, there are clear patterns in group II patients not present in group I.

4 0
3 years ago
Explain the process of an enzyme binding to the active sit of substrate molecule
Luba_88 [7]
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