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zheka24 [161]
2 years ago
5

An automobile assembly line runs for 9 3/4 hours each day. employees work 3/4 hours shift. how many shifts are there in each day

Mathematics
1 answer:
babunello [35]2 years ago
4 0

Answer:

the mixed fraction 9 3/4 means there are 9 4/4 s and one 3/4all togather there are 39/4 divid this by 3/4 to find the no of shifts. 39/4 ÷(3/4)

=39/4. ×4/3=13

13shifts

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What is the measure of the indicated arc in radians?
iogann1982 [59]

Answer:

D is the right one

Step-by-step explanation:

π radian = 180 degree

-> 135 degree = \frac{135}{180} π radian

-> 135 degree = 0.75 * π  radians = 3π/4 radian

5 0
2 years ago
A triangle's height is 10 feet more than its base. If the area of the triangle is 100 square feet, use factoring to find its dim
stiks02 [169]

The base length of the triangle is 10 ft. and the height of the triangle is 20ft.

Step-by-step explanation:

Height = base + 10

Area = 100 square ft

Area of a triangle= (1/2) (b) (h)

100 = (1/2) (b) (b + 10)

200 = b(b) + 10b

b(b) + 10b - 200 = 0

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b ( b + 20) -10(b + 20) = 0

(b-10) (b+20) =0

b = 10 (or) b = -20

Here b is the length and cannot be negative.

So, b = 10ft

h = b + 10

h = 10 + 10

h = 20 ft.

The base length of the triangle is 10 ft. and the height of the triangle is 20ft.

6 0
3 years ago
In ⊙H, Arc I K ≅ Arc J K, mArc I K = (11x + 2)°, and mArc J K = (12x – 7)°.
Bumek [7]

Answer:

202

Step-by-step explanation:

Did it on Edu.

7 0
3 years ago
Read 2 more answers
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
2 years ago
How many different ways can you arrange 100 numbers?
Semenov [28]
10,000 or 100,000 so I hope it helps
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3 years ago
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