0.
It is impossible for 151 to be selected, as it is outside the range of numbers (1 to 100) that can be selected. Therefore the probability is 0.
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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1/27
1/27
125
Step-by-step explanation:
Given that,
a - b = 3
9^(1/2b) /3^a = 3^(2/2b) /3^a
= 3^b/3^a
= 3^(b-a)
= 3^(-3)
= 27^(-1)
= 1/27
27^(1/3b) /9^(1/2a) = 3^(3/3b) /3^(2/2a)
= 3^b/3^a
= 3^(b-a)
= 3^(-3)
= 27^(-1)
= 1/27
125^(1/3a) /25^(1/2b) = 5^(3/3a) /5^(2/2b)
= 5^a/5^b
= 5^(a- b)
= 5^3
= 125
13,986
Step-by-step explanation:
Juss used a calculator, the rest guess
Answer:
8
Step-by-step explanation:
