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grandymaker [24]
4 years ago
14

ill give the brain my duuudes plot the x- and y-intercept to graph this equation y=-1/2x-3. plz plot on graph :))

Mathematics
2 answers:
solniwko [45]4 years ago
6 0

Answer: Check out the attached image below for the x and y intercepts, along with the line that goes through the two points.

To find the y intercept, plug in x = 0 and simplify

y = (-1/2)*x - 3

y = (-1/2)*0 - 3

y = 0 - 3

y = -3

In short, the y intercept is simply the constant at the end as the variable term goes away when x = 0. This is represented by the point (0,-3) as shown in red in the attached image below. This is where the graph crosses the y axis.

--------

To get the x intercept, we do the opposite as before. We plug in y = 0 and solve for x

y = (-1/2)*x - 3

0 = (-1/2)*x - 3

3 = (-1/2)*x

(-1/2)*x = 3

x = -2*3

x = -6

When x = -6, y = 0. So the x intercept is the point (-6,0) as shown as the blue point in the attached image below.

ch4aika [34]4 years ago
3 0

Answer: i have attached my graph

hope this helps


Step-by-step explanation:


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Pavlova-9 [17]
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7 0
3 years ago
An oval track is made by erecting semicircles on each end of a 44 m by 88 m rectangle. Find the length of the track and the area
Dmitry_Shevchenko [17]

Answer:

The length of the track is 247 m.

The area enclosed by the track is  5391 . 76 sq m.

Step-by-step explanation:

The length of the rectangle  = 88 m

The width of the rectangle  =  44 m

Now, as we know the semicircles are at the end of rectangular track.

So, the diameter of semicircles = Width of the rectangle

⇒ The diameter of the semi circle  = 44 m

⇒Radius of the semi circle  = 44/2 = 22 m

TOTAL LENGTH OF TRACK  

= 2 ( Length of rectangle)  + 2 (Circumference of 1 semicircle)

= 2 x (88 m)  + 2 (\frac{2\pi r}{2})

= 176 m + 2 (3.14)(22 m)  = 176 + 71.08 =  247 m

Hence, the length of the track is 247 m

TOTAL AREA OF TRACK  

= (Area of rectangle)  + 2 (Area of 1 semicircle)

= (Length x Width)  +    2 (\frac{\pi r^2}{2})

=  (44  m x 88 m) +  (3.14)(22 m)(22 m)   = (3872  + 1519.76) sq m

=  5391 . 76 sq m

Hence, the area enclosed by the track is  5391 . 76 sq m.

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Answer:

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Step-by-step explanation:

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the diameter for the circle is 12

radius is 6

Area for circle= pi* r²

3.142*6^2=113.112

144-113.112=30.888

30.888/4=7.722

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3 years ago
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Mamont248 [21]
I think it would be:

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3 years ago
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Sav [38]

Answer:

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Step-by-step explanation:

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