1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lina2011 [118]
3 years ago
13

1 Point

Mathematics
1 answer:
Sav [38]3 years ago
6 0

Answer:

50, 52, 54, 55, 56, 56, 64, 65, 68, 74, 74, 76, 77, 77, 80, 81,  90, 91, 95, 99,

Step-by-step explanation:

You might be interested in
Use the "rule of 72" to estimate the doubling time (in years) for the interest rate, and then calculate it exactly. (Round your
Law Incorporation [45]

Answer:

According to the rule of 72, the doubling time for this interest rate is 8 years.

The exact doubling time of this amount is 8.04 years.

Step-by-step explanation:

Sometimes, the compound interest formula is quite complex to be solved, so the result can be estimated by the rule of 72.

By the rule of 72, we have that the doubling time D is given by:

D = \frac{72}{Interest Rate}

The interest rate is in %.

In our exercise, the interest rate is 9%. So, by the rule of 72:

D = \frac{72}{9} = 8.

According to the rule of 72, the doubling time for this interest rate is 8 years.

Exact answer:

The exact answer is going to be found using the compound interest formula.

A = P(1 + \frac{r}{n})^{nt}

In which A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this exercise, we have:

We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.

is double the initial amount, double the principal.

A = 2P

r = 0.09

The interest is compounded anually, so n = 1

A = P(1 + \frac{r}{n})^{nt}

2P = P(1 + \frac{0.09}{1})^{t}

2 = (1.09)^{t}

Now, we apply the following log propriety:

\log_{a} a^{n} = n

So:

\log_{1.09}(1.09)^{t} = \log_{1.09} 2

t = 8.04

The exact doubling time of this amount is 8.04 years.

4 0
4 years ago
I need help fast!!!!!!!!!!!!!!!¡!!!!!¡!!!!!!!!!m!!!!!!​
raketka [301]
I think the answer is shelter B
4 0
3 years ago
Micah has two valuable watches.
BlackZzzverrR [31]

Answer:£149

Step-by-step explanation:

8 0
3 years ago
I need help with this question ??
aliya0001 [1]

Answer:

D

Step-by-step explanation:

x(-3x+4)=x*(-3)+x*4=-3x^2+4x

5 0
3 years ago
Read 2 more answers
Which regular polygon with an apothem of 5 inches, will have a perimeter that is the closest to the circumference of a circle wi
lesantik [10]
The regular polygon with an apothegm of 5 inches, that has a perimeter that is closest to the circumference of a circle with a diameter of 10.8 inches is an octagon. The correct answer is D. 
7 0
3 years ago
Read 2 more answers
Other questions:
  • A circular picture is 8 inches in diameter.
    14·1 answer
  • How do you represent the five in 6.75
    14·1 answer
  • Y = -2/3x + 2<br>y = 3/2x + 9<br>These lines are...​
    14·2 answers
  • when using tables and verbal descriptions to describe a linear relationship why is it useful to convert from one to another
    13·1 answer
  • Sylvia translated the phrase into an algebraic expression and then evaluated it for n=5
    9·2 answers
  • The current in a stream moves at a speed of 8mph. A boat travels 11mi upstream and 11 mi downstream in a total time of 13hr. Wha
    10·1 answer
  • PLEASE HURRY : A container is 40% filled with liquid. The container holds 1560 gallons of liquid. How many gallons of liquid are
    14·2 answers
  • Use the number line to answer the question
    5·1 answer
  • I dont know the answer to this equation<img src="https://tex.z-dn.net/?f=3c-9d%2B7c%2B5d" id="TexFormula1" title="3c-9d+7c+5d" a
    14·1 answer
  • -Solve the following equation -7=-8+|-3+6x|
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!