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murzikaleks [220]
3 years ago
15

A what helps people in developing countries obtain minimal funding to start small businesses

Mathematics
1 answer:
seropon [69]3 years ago
7 0
The correct answer is the word, "GRANT"

People in developing countries can find minimal funding<span> through small-business </span>grants to start small businesses. Grants are basically free money<span>. Unlike loans, they are financial awards that don't have to be paid back.</span>
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2x + 5 &gt; 9 and 5x less than or equal to 30
tatuchka [14]
2x + 5 > 9
so 2x > 9-5
   2x > 4
x > 2

5x <= 30
x <= 6


answer is   2 < x <= 6 

or interval notation it is (2, 6]
6 0
4 years ago
Please see attached image and help with these absolute value problems - thank you
Novay_Z [31]

Answer:

{-infinity, infinity}

no solution

Step-by-step explanation:

|x| +15≥4

Subtract 15 from each side

|x| +15-15≥4-15

|x| ≥-11

This is always true so x can be and real number

{-infinity, infinity}

-2|5x+3| = 8

Divide by -2

-2/-2|5x+3| = 8/-2

|5x+3| = -4

This can never happen because absolute values are zero or greater

no solution

6 0
3 years ago
the ratio of the number of adults to the number of students at the problem has to be 1 :10 Last year there were 477 more student
JulsSmile [24]
About 48 adults. I think.
4 0
3 years ago
In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen
Mashcka [7]

Answer:

a) P' = P

   P(t) = 24e^{0.693t} where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

\frac{dP}{dt} = P

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

P(t) = P_0e^{kt}

where P_0 = 24 is the initial population

After 6 month (t = 1), the population is doubled to 48

P(1) = 24e^k = 48

e^k = 2

k = ln(2) = 0.693

Therefore P(t) = 24e^{0.693t}

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

24e^{0.693t} = 1000000

e^{0.693t} = 1000000 / 24 = 41667

0.693t = ln(41667) = 10.64

t = 10.64 / 0.693 = 15.35

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. P' = P_0ke^{kt}

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

24e^{0.5k) = 48

0.5k = ln2 = 0.693

k = 1.386

Therefore, P' = 1.386*24e^{1.386t}

At the mid of the 3rd year, where t = 2.5, we can calculate P'

P' = 1.386*24e^{1.386*2.5} = 1064.67 rabbits/year

4 0
3 years ago
Help me please this is due today :((<br> Show all work for it pleaseee
Rudik [331]

Answer:

Length C, B= 90 mi

Step-by-step explanation:

The small square in the corner in any shape always represent 90°

<em>Hope it helps!!</em>

5 0
2 years ago
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