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DIA [1.3K]
3 years ago
6

What are three anticipated uses of nitrogen when it is compressed to 2.4 million atmospheres? ​

Chemistry
1 answer:
Katen [24]3 years ago
8 0

Answer:

Explosive, Propellant and Semiconductor

Explanation:

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Adam observed properties of four different waves and
cupoosta [38]

Answer:

D)The sound quality for these waves cannot be compared.

Explanation:

I've done it on e2020

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3 years ago
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True or false if an object displaces 50 ml of water the object's volume is 50mL
andrew11 [14]

Answer:

True

Explanation:

The volume of water displaced by an object completely submerged is its actual volume. It implies that in the container the object create a space of size for itself which is the volume of the object. This approach is used in calculating the density of many irregular solids from their measured masses.

6 0
3 years ago
A chemist needs 0.550 mol selenium for a reaction. What mass of selenium should a chemist use?
-BARSIC- [3]

Answer:

The chemist would require to use 43.43 grams.

Explanation:

In order to solve this problem we need to know<u> how much do 0.550 moles of selenium weigh</u>. To do that we use selenium's<em> molar mass </em>and multiply it by the given number of moles:

  • 0.550 mol * 78.96 g/mol = 43.43 g

The chemist would require to use 43.43 grams.

4 0
3 years ago
A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

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3 years ago
Describe Write your own caption for this photo.
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Sit by the fire to warm up

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