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3 years ago

Will a precipitate form from Pb(NO3)2(aq) and HCl(aq)?

1 answer:

5 0

1. Write out the formula Pb(NO3)2 (aq) + 2HCl (aq) ----> PbCl2 + 2HNO3 2. Use solubility guidelines (gotta memorize 'em) for the products to see if a solid forms Nitrates are always soluble so 2HNO3 (aq) Chlorides (Cl) are always soluble except for when you mix them with copper, lead, mercury, or silver. Since you mixed it with lead (Pb) it is solid and forms a precipitate. PbCl2 (s)

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What is the energy for each question in Joules?

beks73 [17]

Answer:

Hello, there!

In order to solve problems like this DO PEMDAS

The Exponent:

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And

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So, this means that your answer would be

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kjExplanation:

7 0

2 years ago

In the hypothetical reaction below, substance A is consumed at a rate of 2.0 mol/L·s. If this reaction is at dynamic equilibrium

vazorg [7]

Dynamic equilibrium means that the proportion is equal. The fact that the equation is at equilibrium suggests that the equation is balanced and therefore the answer must be 2.0 mol because that allows the products and reactants to level out...

6 0

3 years ago

Read 2 more answers

The density of a pure substance is its mass per unit volume. The density of cresol has been measured to be 1024 g/L . Calculate

Ierofanga [76]

Answer: The mass of 405 ml of cresol is 415 grams

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{volume}$

Given : Density of cresol = 1024 g/L

Volume of cresol = 405 ml = 0.405 L ( 1L=1000ml)

Putting in the values we get:

$1024g/L=\frac{mass}{0.405L}$

$mass=1024g/L\times 0.405L=415g$

Thus mass of 405 ml of cresol is 415 grams

3 0

2 years ago

A chemist adds 0.50L of a 0.485 M copper(II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper(II)

den301095 [7]

Explanation:

It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.

Number of millimoles = Molarity × Volume

As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.

Therefore, putting the given values into the above formula as follows.

Number of millimoles = Molarity × Volume

= 0.485 M × 500 mL

= 242.5

Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.

4 0

3 years ago

An unknown gas effuses at one half the speed of oxygen. What is the molar mass of the unknown? It is either HBr or HI. Which gas

sertanlavr [38]

Answer:

HI.

Explanation:

Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.

Rate of effusion ∝ 1/√molar mass.

(Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).

An unknown gas effuses at one half the speed of that of oxygen.

∵ Rate of effusion of unknown gas = 1/2 (Rate of effusion of O₂)

∴ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = 2.

Molar mass of O₂ = 32.0 g/mol.

∵ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).

∴ 2.0 = (√molar mass of unknown gas) / √32.0.

( √molar mass of unknown gas) = 2.0 x √32.0

By squaring the both sides:

∴ molar mass of unknown gas = (2.0 x √32.0)² = 128 g/mol.

∴ The molar mass of sulfur dioxide = 80.91 g/mol and the molar mass of HI = 127.911 g/mol.

So, the unknown gas is HI.

5 0

2 years ago