Answer:
Hello, there!
In order to solve problems like this DO PEMDAS
The Exponent:
So, equals 4
Your problem becomes
Now we have to do what is in the (
( the is a )
And
Problem becomes
So, this means that your answer would be
Good luck on your assignment and enjoy your day!
kjExplanation:
Dynamic equilibrium means that the proportion is equal. The fact that the equation is at equilibrium suggests that the equation is balanced and therefore the answer must be 2.0 mol because that allows the products and reactants to level out...
Answer: The mass of 405 ml of cresol is 415 grams
Explanation:
Density is defined as the mass contained per unit volume.

Given : Density of cresol = 1024 g/L
Volume of cresol = 405 ml = 0.405 L ( 1L=1000ml)
Putting in the values we get:


Thus mass of 405 ml of cresol is 415 grams
Explanation:
It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.
Number of millimoles = Molarity × Volume
As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.
Therefore, putting the given values into the above formula as follows.
Number of millimoles = Molarity × Volume
= 0.485 M × 500 mL
= 242.5
Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.
Answer:
HI.
Explanation:
- Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.
Rate of effusion ∝ 1/√molar mass.
- <em>(Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).</em>
- An unknown gas effuses at one half the speed of that of oxygen.
∵ Rate of effusion of unknown gas = 1/2 (Rate of effusion of O₂)
∴ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = 2.
Molar mass of O₂ = 32.0 g/mol.
∵ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).
∴ 2.0 = (√molar mass of unknown gas) / √32.0.
(
√molar mass of unknown gas) = 2.0 x √32.0
By squaring the both sides:
∴ molar mass of unknown gas = (2.0 x √32.0)² = 128 g/mol.
∴ The molar mass of sulfur dioxide = 80.91 g/mol and the molar mass of HI = 127.911 g/mol.
<em>So, the unknown gas is HI.</em>
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