Question

If a rigid can of volume 10.0 L starts at a temperature of 27 oC and 800.0 torr and is heated to 327 oC, what is the new pressure in torr?

Answer 1

Answer: The final pressure is 1600 torr.

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay Lussac' Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant volume.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=800.0torr\\T_1=27^oC=(27+273)K=300K\\P_2=?\\T_2=327^0C=(327+273)K=600K$

Putting values in above equation, we get:

$\frac{800.0torr}{300K}=\frac{P_2}{600K}\\\\P_2=1600torr$

Thus the final pressure is 1600 torr.