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Nezavi [6.7K]
3 years ago
15

How is light generated?

Physics
1 answer:
Fudgin [204]3 years ago
5 0
<span>electrons change momentum, some of them slough off photons. And some of those photons have energy in the visible light range of the electro-magnetic spectrum. </span>
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Infrared light of wavelength 2.5 µm illuminates a 0.20-mm-diameter hole. What is the angle of the first dark fringe in radians?
stepan [7]

Answer:

Θ=0.01525 rad

or

Θ=0.87°

Explanation:

Given data

wavelength λ=2.5 µm =2.5×10⁻⁶m

Diameter d=0.20 mm =0.20×10⁻³m

To find

Angle Θ in radians and degree

Solution

Circular apertures have first dark fringe at

Θ=(1.22λ)/d

Substitute the given values

So

Θ=[1.22(2.5×10⁻⁶m)]/0.20×10⁻³m

Θ=0.01525 rad

or

Θ=0.87°

6 0
3 years ago
Match the following. Column A 1. Torque 2. Centre of gravity 3. Plumb line Column B A. Line of centre of gravity B. Maximum cons
gregori [183]

Answer:

1. Torque → F. Study of forces

2. C.O.G → D. Point of action of weight.

3. Plumb line → A. Line of C.O.G

8 0
3 years ago
A 4-kg block and a 2-kg block can move on the horizontal frictionless surface. The blocks are accelerated by a+12-N force that p
lozanna [386]

Answer:

F_n = -4 N

Explanation:

Net external force that exerted on the block is given as

F_{net} = (m_1 + m_2) a

here we know that

F = 12 N

m_1 = 4 kg

m_2 = 2 kg

now we have

12 = (4 + 2) a

so we have

a = 2 m/s^2

now the force exerted by bigger block on smaller block is given as

F_n = ma

F_n = (2 \times 2)

F_n = 4 N

now we know that two blocks will exert equal and opposite force on each other

so here the force exerted by 2 kg block on 4 kg block will be

F_n = -4 N

5 0
3 years ago
A plane mirror is placed to the right of an object. The image formed by the mirror will be a
guajiro [1.7K]

Answer:

A plane mirror is placed to the right of an object. The image formed by the mirror will be a virtual image that appears to be on the left of the mirror.

Explanation:

3 0
3 years ago
Read 2 more answers
g 2. In a laboratory experiment on standing waves a string 3.0 ft long is attached to the prong of an electrically driven tuning
abruzzese [7]

Answer:

The tension in string will be "3.62 N".

Explanation:

The given values are:

Length of string:

l = 3 ft

or,

 = 0.9144 m

frequency,

f = 60 Hz

Weight,

= 0.096 lb

or,

= 0.0435 kgm/s²

Now,

The mass will be:

= \frac{0.0435}{9.8}

= 0.0044 \ kg

As we know,

⇒  \lambda=\frac{2L}{n}

On substituting the values, we get

⇒     =\frac{2\times 0.9144}{4}

⇒     =0.4572 \ m

or,

⇒  v=f \lambda

⇒      =0.4572\times 60

⇒      =27.432 \ m/s

Now,

⇒  v=\sqrt{\frac{T}{\mu} }

or,

⇒  T=\frac{m}{l}\times v^2

On putting the above given values, we get

⇒      =\frac{0.0044}{0.9144}\times (27.432)^2

⇒      =\frac{752.51\times 0.0044}{0.9144}

⇒      =3.62 \ N

7 0
3 years ago
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