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3 years ago

How would the seasons be different if Earth were not tilted on its Axis?

Physics

2 answers:

Alja [10]3 years ago

6 0

Answer:

no seasons

Explanation:

if the earth weren't tilted, it would rotate like that as it revolved around the sun, and we wouldn't have seasons—only areas that were colder (near the poles) and warmer (near the Equator).

spin [16.1K]3 years ago

6 0

If the earth was not tilted on its axis there would be no seasons

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A spring has a 12 cm length. When a 200-g mass is hung from the spring, it extends to 27 cm. The hanging mass were pulled downwa

BartSMP [9]

Answer:

The equation of the time-dependent function of the position is $x(t)=5\cos(8.08t)$

(b) is correct option.

Explanation:

Given that,

Length = 12 cm

Mass = 200 g

Extend distance = 27 cm

Distance = 5 cm

Phase angle =0°

We need to calculate the spring constant

Using formula of restoring force

$F=kx$

$mg=kx$

$k=\dfrac{mg}{x}$

$k=\dfrac{200\times10^{-3}\times9.8}{(27-12)\times10^{2}}$

$k=13.06\ N/m$

We need to calculate the time period

Using formula of time period

$T=2\pi\sqrt{\dfrac{m}{k}}$

Put the value into the formula

$T=2\pi\sqrt{\dfrac{0.2}{13.6}}$

$T=0.777\ sec$

At t = 0, the maximum displacement was 5 cm

So, The equation of the time-dependent function of the position

$x(t)=A\cos(\omega t)$

Put the value into the formula

$x(t)=5\cos(2\pi\times f\times t)$

$x(t)=5\cos(2\pi\times\dfrac{1}{T}\times t)$

$x(t)=5\cos(2\pi\times\dfrac{1}{0.777}\times t)$

$x(t)=5\cos(8.08t)$

Hence, The equation of the time-dependent function of the position is $x(t)=5\cos(8.08t)$

8 0

3 years ago

Help ASAP <br> Just answer the first question for me please!

Usimov [2.4K]

Answer:

Im pretty sure its b

4 0

3 years ago

Occurs when fuel rods produce too much heat

gizmo_the_mogwai [7]

it is known as the
nuclear meltdown

7 0

4 years ago

A student coils a copper wire around a bar magnet. What action will cause the device to generate electricity?

kolbaska11 [484]

I hope the wire is not wound too tightly around the bar magnet.
The device will generate electrical energy when the bar magnet
is moving in or out of the coil of wire.

6 0

3 years ago

An athlete does one push-up period in the process, she moves half of her body weight, 250 N, a distance of 20 cm, this distance

ioda

In the push-up, the athlete's weight (or force) of 250 N moves through a distance of 20 cm.

By definition,
Work = force * distance.

Therefore, work done in one push-up is
$W=(250 \, N)*(20 \, cm)*(10^{-2} \, \frac{cm}{m}) = 50 \, J$

Note that 1 J = 1 N-m.

Answer: 1 J

3 0

4 years ago