<span>change in velocity = final velocity - initial velocity = v - u
for comet:
uc = initial velocity of comet (before impact)
vc = final velocity of comet
mc= mass of comet
uc = 40000 kmph
vc = ?
mc= 10 x 10^14 kg
for probe:
up = initial velocity of probe (before impact)
vp = final velocity of probe
mp= mass of probe
up= 37000 kmph
vp= ?
mp= 372 kg
Now,
by principle of conservation of momentum
(mc x uc) - (mp x up) = (mc x vc) + (mp x vp)
Since probe is in comet after collision, vp= vc = V
then,
(mc x uc) - (mp x up) = V (mc + mp )
V = [(mc x uc) - (mp x up)] / (mc + mp )
= ((10 × 10^14 × 40000) - (372 × 37000)) ÷ ((10 × 10^14) + 372)
= ???
then,
change in velocity of the comet = ??? - (40000) =
</span>
C does not represent a benefit, so that seems most logical.
A) they comprised.
B) at least ones listening
D) nothings wring with that
Inclined plane is a simple machine that is a straight slanted surface.
First thing to do is to draw the system described above. Then, write an equation for the forces present.
<span>
</span>Σ<span>F = Fg - Ff
</span><span>0 = mgsin</span><span>∅</span><span> - umgcos</span><span>∅</span><span>0 = gsin</span><span>∅</span><span> - ugcos</span><span>∅</span><span>
u = tan</span><span>∅
</span>∅(max) = tan^-1 (u)<span>
</span>
Answer:
Water normally freezes at 0°C (32°F). Salt lowers the freezing temperature. (That is, it can remain a liquid at much lower temperatures.)
When sprinkled on ice, the salt lowers the freezing temperature of the water which effectively melts the ice when the salt dissolves into it. There is a limit to how low it can reduce the temperature, though. If the temperature drops below -9°C (15°F), it's too cold for the salt to dissolve into the ice.
When making ice cream, the salt lowers the temperature of the ice and water sufficiently enough to freeze the cream.
