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antoniya [11.8K]
3 years ago
7

A 4-kg block and a 2-kg block can move on the horizontal frictionless surface. The blocks are accelerated by a+12-N force that p

ushes the larger block against the smaller one. Determine the force that the 2-kg block exerts on the 4-kg block.
A) -4 N
B) -12 N
C) 0 N
D) +4 N
E) +8 N
Physics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

F_n = -4 N

Explanation:

Net external force that exerted on the block is given as

F_{net} = (m_1 + m_2) a

here we know that

F = 12 N

m_1 = 4 kg

m_2 = 2 kg

now we have

12 = (4 + 2) a

so we have

a = 2 m/s^2

now the force exerted by bigger block on smaller block is given as

F_n = ma

F_n = (2 \times 2)

F_n = 4 N

now we know that two blocks will exert equal and opposite force on each other

so here the force exerted by 2 kg block on 4 kg block will be

F_n = -4 N

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