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AleksAgata [21]
3 years ago
12

Scientific models have two basic types. Please select the best answer from the choices provided T F

Physics
2 answers:
Ede4ka [16]3 years ago
6 0

Answer:

Scientific models have two basic types. FALSE.

Hoped I helped

evablogger [386]3 years ago
3 0

\huge{\mathcal{\purple{A}\green{n}\pink{s}\blue{w}\purple{E} \green{r}}}

  • <em>FALSE</em>

<em><u>THERE ARE THREE MODELS</u></em>

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- Here is some reasons some earthquakes are more dangerous than others:

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3 years ago
Read 2 more answers
At what height above the ground must a mass of 10 kg be to have a potential energy equal in value to the kinetic energy possesse
Paladinen [302]

Answer:

20 m

Explanation:

We'll begin by calculating the kinetic energy of the mass. This can be obtained as follow:

Mass (m) = 10 kg

Velocity (v) = 20 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 10 × 20²

KE = 5 × 400

KE = 2000 J

Finally, we shall the height to which the mass must be located in order to have potential energy that is the same as the kinetic energy. This can be obtained as follow:

Mass (m) = 10 kg

Acceleration due to gravity (g) = 10 m/s²

Potential energy (PE) = Kinetic energy (KE) = 2000 J

Height (h) =..?

PE = mgh

2000 = 10 × 10 × h

2000 = 100 × h

Divide both side by 100

h = 2000 / 100

h = 20 m

Thus, the object must be located at a height of 20 m in order to have potential energy that is the same as the kinetic energy.

5 0
3 years ago
Ninety percent of stars in the solar system are :
sergiy2304 [10]
90% of stars in the solar system are main sequence stars.
3 0
3 years ago
Two point charges of +20.0 μC and -8.00 μC are separated by a distance of 20.0 cm. What is the intensity of electric field E mid
algol13

Answer:

The intensity of the net electric field will:

E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C

Explanation:

Here we need first find the electric field due to the first charge at the midway point.

The electric field equation is given by:

|E_{1}|=k\frac{q_{1}}{d^{2}}

Where:

  • k is Coulomb's constant
  • q(1) is 20.00 μC or 20*10⁻⁶ C
  • d is the distance from q1 to the midpoint (d=10.0 cm)

So, we will have:

|E_{1}|=(9*10^{9})\frac{20*10^{-6}}{0.1^{2}}

|E_{1}|=1.8*10^{7}\: N/C

The direction of E1 is to the right of the midpoint.

Now, the second electric field is:

|E_{2}|=k\frac{q_{2}}{d^{2}}

|E_{2}|=(9*10^{9})\frac{8*10^{-6}}{0.1^{2}}

|E_{2}|=7.2*10^{6}\: N/C

The direction of E2 is to the right of the midpoint because the second charge is negative.

Finally, the intensity of the net electric field will:

E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C

I hope it helps you!

5 0
3 years ago
Elaborate on the suitability of "cola" type drinks to polish chrome surfaces.
nexus9112 [7]
The answer is t<span>he phosphoric acid in cola easily removes dirt and grime.   The </span>"cola" type drinks is suitable to polish chrome surfaces. Cola contains a very diluted solution of phosphoric acid, which can  remove rust, dirt, and grime from chrome surface. 
3 0
4 years ago
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