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3 years ago

What is the value of f(x) = 2/3 x + 1/4 when x = 6?

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

4 0

Answer:

4 1/4

Step-by-step explanation:

f(x) = 2/3(6) + 1/4

f(x) = 4 + 1/4

f(x) = 4 1/4(4.25)

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A used-boat dealership buys a boat for $2800 and then sells it for $4000. What is the percent increase?

Rudik [331]

Answer:

Step-by-step explanation:

percent increase = increase divided by original number x 100

increase is the difference between the two numbers...

new number - original number.....4000 - 2800 = 1200

percent increase = (1200 / 2800) x 100

= 0.42857 (round to .4286) x 100

= 42.86 %.....if you need it rounded to the nearest percent, it would be 43% increase

6 0

4 years ago

Match the equation with the step needed to solve it.

viva [34]

1) Subtract 2m
2) Subtract m
3) Add 1
4) Subtract 2
5) Add 2
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8 0

3 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

4 years ago

Literal Equations? Anyone? The problems are in the picture! Show solution please! Thanks in advance!

lapo4ka [179]

The way to solve is using order of operation PEMDAS. Its very easy. You should be able to solve it yourself. I'll give you the first 3 answers:
1. g/6=x
2. x=1/2u+1
3. z-m=x
I would give you all the answers but it would be best if you did it yourself. You teacher and parents would be much happier if you learnt the skill. Hope this answer helps! Mark as brainliest! :)

4 0

3 years ago

6x^2 - 9x + 3<br> - (8x²+ 7x - 1)

Solnce55 [7]

Answer:

-2x² - 16x + 4

Step-by-step explanation:

Step 1: Write out expression

6x² - 9x + 3 - (8x² + 7x - 1)

Step 2: Distribute negative

6x² - 9x + 3 - 8x² - 7x + 1

Step 3: Combine like terms (x²)

-2x² - 9x + 3 - 7x + 1

Step 4: Combine like terms (x)

-2x² - 16x + 3 + 1

Step 5: Combine like terms (constants)

-2x² - 16x + 4

8 0

3 years ago

Read 2 more answers